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A15018. 2-Letter Strings

编程题 普及/提高-

题目描述

Given $n$ strings, each of length $2$ , consisting of lowercase Latin alphabet letters from 'a' to 'k', output the number of pairs of indices $(i, j)$ such that $i < j$ and the $i$ -th string and the $j$ -th string differ in exactly one position.

In other words, count the number of pairs $(i, j)$ ( $i < j$ ) such that the $i$ -th string and the $j$ -th string have exactly one position $p$ ( $1 \leq p \leq 2$ ) such that ${s_{i}}_{p} \neq {s_{j}}_{p}$ .

The answer may not fit into 32-bit integer type, so you should use 64-bit integers like long long in C++ to avoid integer overflow.

输入格式

The first line of the input contains a single integer $t$ ( $1 \le t \le 100$ ) — the number of test cases. The description of test cases follows.

The first line of each test case contains a single integer $n$ ( $1 \le n \le 10^5$ ) — the number of strings.

Then follows $n$ lines, the $i$ -th of which containing a single string $s_i$ of length $2$ , consisting of lowercase Latin letters from 'a' to 'k'.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$ .

输出格式

For each test case, print a single integer — the number of pairs $(i, j)$ ( $i < j$ ) such that the $i$ -th string and the $j$ -th string have exactly one position $p$ ( $1 \leq p \leq 2$ ) such that ${s_{i}}_{p} \neq {s_{j}}_{p}$ .

Please note, that the answer for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language (like long long for C++).

输入输出样例

输入 #1
4
6
ab
cb
db
aa
cc
ef
7
aa
bb
cc
ac
ca
bb
aa
4
kk
kk
ab
ab
5
jf
jf
jk
jk
jk
输出 #1
5
6
0
6

说明/提示

For the first test case the pairs that differ in exactly one position are: ("ab", "cb"), ("ab", "db"), ("ab", "aa"), ("cb", "db") and ("cb", "cc").

For the second test case the pairs that differ in exactly one position are: ("aa", "ac"), ("aa", "ca"), ("cc", "ac"), ("cc", "ca"), ("ac", "aa") and ("ca", "aa").

For the third test case, the are no pairs satisfying the conditions.
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