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A16306. Cover in Water

编程题 普及/提高-
知识点

题目描述

Filip has a row of cells, some of which are blocked, and some are empty. He wants all empty cells to have water in them. He has two actions at his disposal:

- $1$ — place water in an empty cell.
- $2$ — remove water from a cell and place it in any other empty cell.

If at some moment cell $i$ ( $2 \le i \le n-1$ ) is empty and both cells $i-1$ and $i+1$ contains water, then it becomes filled with water.

Find the minimum number of times he needs to perform action $1$ in order to fill all empty cells with water.

Note that you don't need to minimize the use of action $2$ . Note that blocked cells neither contain water nor can Filip place water in them.

输入格式

Each test contains multiple test cases. The first line contains the number of test cases $t$ ( $1 \le t \le 100$ ). The description of the test cases follows.

The first line of each test case contains a single integer $n$ ( $1 \le n \le 100$ ) — the number of cells.

The next line contains a string $s$ of length $n$ . The $i$ -th character of $s$ is '.' if the cell $i$ is empty and '\#' if cell $i$ is blocked.

输出格式

For each test case, output a single number — the minimal amount of actions $1$ needed to fill all empty cells with water.

输入输出样例

输入 #1
5
3
...
7
##....#
7
..#.#..
4
####
10
#...#..#.#
输出 #1
2
2
5
0
2

说明/提示

Test Case 1

In the first test case, Filip can put water in cells $1$ and $3$ . As cell $2$ is between $2$ cells with water, it gets filled with water too.

Test Case 2

In the second case, he can put water sources in cells $3$ and $5$ . That results in cell $4$ getting filled with water. Then he will remove water from cell $5$ and place it into cell $6$ . As cell $5$ 's neighbors, cell $4$ and cell $6$ , have water in them, cell $5$ also gets filled with water. You can see the illustration of this case below.

![](/uploads/acgo/image/46a97f8265210112_00820dde28f8.jpeg) Operations in the second test case. White cells are empty, grey ones are blocked, and blue ones are water.Test Case 3

In the third case, he can put water in all the empty cells. That requires $5$ actions of type $1$ .

Test Case 4

In the fourth case, there are no empty cells. Therefore, he does not have to put any water in them.

Test Case 5

In the fifth test case, there exists a sequence of actions that requires only $2$ type $1$ actions.
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