A16166. To My Critics
编程题
普及/提高-
知识点
题目描述
Suneet has three digits $a$ , $b$ , and $c$ .
Since math isn't his strongest point, he asks you to determine if you can choose any two digits to make a sum greater or equal to $10$ .
Output "YES" if there is such a pair, and "NO" otherwise.
Since math isn't his strongest point, he asks you to determine if you can choose any two digits to make a sum greater or equal to $10$ .
Output "YES" if there is such a pair, and "NO" otherwise.
输入格式
The first line contains a single integer $t$ ( $1 \leq t \leq 1000$ ) — the number of test cases.
The only line of each test case contains three digits $a$ , $b$ , $c$ ( $0 \leq a, b, c \leq 9$ ).
The only line of each test case contains three digits $a$ , $b$ , $c$ ( $0 \leq a, b, c \leq 9$ ).
输出格式
For each test case, output "YES" if such a pair exists, and "NO" otherwise.
You can output the answer in any case (for example, the strings "yEs", "yes", "Yes" and "YES" will be recognized as a positive answer).
You can output the answer in any case (for example, the strings "yEs", "yes", "Yes" and "YES" will be recognized as a positive answer).
输入输出样例
输入 #1
5 8 1 2 4 4 5 9 9 9 0 0 0 8 5 3
输出 #1
YES NO YES NO YES
说明/提示
For the first test case, by choosing the digits $8$ and $2$ we can obtain a sum of $8 + 2 = 10$ which satisfies the condition, thus the output should be "YES".
For the second test case, any combination of chosen digits won't be at least $10$ , thus the output should be "NO" (note that we can not choose the digit on the same position twice).
For the third test case, any combination of chosen digits will have a sum equal to $18$ , thus the output should be "YES".
For the second test case, any combination of chosen digits won't be at least $10$ , thus the output should be "NO" (note that we can not choose the digit on the same position twice).
For the third test case, any combination of chosen digits will have a sum equal to $18$ , thus the output should be "YES".