测评会员优惠活动进行中 · 开通 VIP,有效期内测评不限次 VIP 优惠中 · 测评不限次 立即查看

A15705. Negatives and Positives

编程题 普及/提高-

题目描述

Given an array $a$ consisting of $n$ elements, find the maximum possible sum the array can have after performing the following operation any number of times:

- Choose $2$ adjacent elements and flip both of their signs. In other words choose an index $i$ such that $1 \leq i \leq n - 1$ and assign $a_i = -a_i$ and $a_{i+1} = -a_{i+1}$ .

输入格式

The input consists of multiple test cases. The first line contains an integer $t$ ( $1 \leq t \leq 1000$ ) — the number of test cases. The descriptions of the test cases follow.

The first line of each test case contains an integer $n$ ( $2 \leq n \leq 2\cdot10^5$ ) — the length of the array.

The following line contains $n$ space-separated integers $a_1,a_2,\dots,a_n$ ( $-10^9 \leq a_i \leq 10^9$ ).

It is guaranteed that the sum of $n$ over all test cases does not exceed $2\cdot10^5$ .

输出格式

For each test case, output the maximum possible sum the array can have after performing the described operation any number of times.

输入输出样例

输入 #1
5
3
-1 -1 -1
5
1 5 -5 0 2
3
1 2 3
6
-1 10 9 8 7 6
2
-1 -1
输出 #1
1
13
6
39
2

说明/提示

For the first test case, by performing the operation on the first two elements, we can change the array from $[-1, -1, -1]$ to $[1, 1, -1]$ , and it can be proven this array obtains the maximum possible sum which is $1 + 1 + (-1) = 1$ .

For the second test case, by performing the operation on $-5$ and $0$ , we change the array from $[1, 5, -5, 0, 2]$ to $[1, 5, -(-5), -0, 2] = [1, 5, 5, 0, 2]$ , which has the maximum sum since all elements are non-negative. So, the answer is $1 + 5 + 5 + 0 + 2 = 13$ .

For the third test case, the array already contains only positive numbers, so performing operations is unnecessary. The answer is just the sum of the whole array, which is $1 + 2 + 3 = 6$ .
上一题 去做题 下一题