A12343 | Almost Regular Bracket Sequence
时间限制1s
内存限制256MB
通过 / 提交0/0
题目描述
You are given a bracket sequence $s$ consisting of $n$ opening '(' and closing ')' brackets.
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters '1' and '+' between the original characters of the sequence. For example, bracket sequences "()()", "(())" are regular (the resulting expressions are: "(1)+(1)", "((1+1)+1)"), and ")(" and "(" are not.
You can change the type of some bracket $s_i$ . It means that if $s_i = $ ')' then you can change it to '(' and vice versa.
Your task is to calculate the number of positions $i$ such that if you change the type of the $i$ -th bracket, then the resulting bracket sequence becomes regular.
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters '1' and '+' between the original characters of the sequence. For example, bracket sequences "()()", "(())" are regular (the resulting expressions are: "(1)+(1)", "((1+1)+1)"), and ")(" and "(" are not.
You can change the type of some bracket $s_i$ . It means that if $s_i = $ ')' then you can change it to '(' and vice versa.
Your task is to calculate the number of positions $i$ such that if you change the type of the $i$ -th bracket, then the resulting bracket sequence becomes regular.
输入格式
The first line of the input contains one integer $n$ ( $1 \le n \le 10^6$ ) — the length of the bracket sequence.
The second line of the input contains the string $s$ consisting of $n$ opening '(' and closing ')' brackets.
The second line of the input contains the string $s$ consisting of $n$ opening '(' and closing ')' brackets.
输出格式
Print one integer — the number of positions $i$ such that if you change the type of the $i$ -th bracket, then the resulting bracket sequence becomes regular.
输入输出样例
输入 #1
6 (((())
输出 #1
3
输入 #2
6 ()()()
输出 #2
0
输入 #3
1 )
输出 #3
0
输入 #4
8 )))(((((
输出 #4
0
暂无题解
C++ 编辑器
输入
输出
可保存默认模板;新题优先使用已保存模板。
当前快捷键仅展示,暂不支持修改。
- 撤销
Ctrl / ⌘ + Z - 重做
Ctrl / ⌘ + Y - 查找
Ctrl / ⌘ + F - 全选
Ctrl / ⌘ + A - 复制
Ctrl / ⌘ + C - 剪切
Ctrl / ⌘ + X - 粘贴
Ctrl / ⌘ + V - 自动排版
工具栏排版按钮 - 草稿保存
编辑时自动保存到本机
历史
提交记录
状态说明时间源码
AI
作答助手
你好,我是作答助手。可以问思路、复杂度、样例含义或代码报错原因;不会直接给出完整 AC 代码。
确定要清空代码吗?
提交通过
评测结果:Accepted