A992. Haircut--Gold
编程题
普及+/提高
知识点
题目描述
Tired of his stubborn cowlick, Farmer John decides to get a haircut. He has
$N$ ($1\le N\le 10^5$) strands of hair arranged in a line, and strand $i$ is
initially $A_i$ micrometers long ($0\le A_i\le N$). Ideally, he wants his hair
to be monotonically increasing in length, so he defines the "badness" of his
hair as the number of inversions: pairs $(i,j)$ such that $i < j$ and $A_i >
A_j$.
For each of $j=0,1,\ldots,N-1$, FJ would like to know the badness of his hair
if all strands with length greater than $j$ are decreased to length exactly
$j$.
(Fun fact: the average human head does indeed have about $10^5$ hairs!)
$N$ ($1\le N\le 10^5$) strands of hair arranged in a line, and strand $i$ is
initially $A_i$ micrometers long ($0\le A_i\le N$). Ideally, he wants his hair
to be monotonically increasing in length, so he defines the "badness" of his
hair as the number of inversions: pairs $(i,j)$ such that $i < j$ and $A_i >
A_j$.
For each of $j=0,1,\ldots,N-1$, FJ would like to know the badness of his hair
if all strands with length greater than $j$ are decreased to length exactly
$j$.
(Fun fact: the average human head does indeed have about $10^5$ hairs!)
输入格式
The first line contains $N$.
The second line contains $A_1,A_2,\ldots,A_N.$
The second line contains $A_1,A_2,\ldots,A_N.$
输出格式
For each of $j=0,1,\ldots,N-1$, output the badness of FJ's hair on a new line.
Note that the large size of integers involved in this problem may require the
use of 64-bit integer data types (e.g., a "long long" in C/C++).
Note that the large size of integers involved in this problem may require the
use of 64-bit integer data types (e.g., a "long long" in C/C++).
输入输出样例
输入 #1
5 5 2 3 3 0
输出 #1
0 4 4 5 7
说明/提示
The fourth line of output describes the number of inversions when FJ's hairs
are decreased to length 3. Then $A=[3,2,3,3,0]$ has five inversions:
$A_1>A_2,\,A_1>A_5,\,A_2>A_5,\,A_3>A_5,$ and $A_4>A_5$.
are decreased to length 3. Then $A=[3,2,3,3,0]$ has five inversions:
$A_1>A_2,\,A_1>A_5,\,A_2>A_5,\,A_3>A_5,$ and $A_4>A_5$.