A877 | Counting Liars--Bronze
来源USACO
时间限制1s
内存限制128MB
通过 / 提交0/0
题目描述
Bessie the cow is hiding somewhere along the number line. Each of Farmer
John's $N$ other cows ($1\le N\le 1000$) have a piece of information to share:
the $i$-th cow either says that Bessie is hiding at some location less than or
equal to $p_i$, or that Bessie is hiding at some location greater than or
equal to $p_i$ ($0\le p_i\le 10^9$).
Unfortunately, it is possible that no hiding location is consistent with the
answers of all of the cows, meaning that not all of the cows are telling the
truth. Count the minimum number of cows that must be lying.
John's $N$ other cows ($1\le N\le 1000$) have a piece of information to share:
the $i$-th cow either says that Bessie is hiding at some location less than or
equal to $p_i$, or that Bessie is hiding at some location greater than or
equal to $p_i$ ($0\le p_i\le 10^9$).
Unfortunately, it is possible that no hiding location is consistent with the
answers of all of the cows, meaning that not all of the cows are telling the
truth. Count the minimum number of cows that must be lying.
输入格式
The first line contains $N$.
The next $N$ lines each contain either L or G, followed by an integer $p_i$. L
means that the $i$-th cow says that Bessie's hiding location is less than or
equal to $p_i$, and G means that $i$-th cow says that Bessie's hiding location
is greater than or equal to $p_i$.
The next $N$ lines each contain either L or G, followed by an integer $p_i$. L
means that the $i$-th cow says that Bessie's hiding location is less than or
equal to $p_i$, and G means that $i$-th cow says that Bessie's hiding location
is greater than or equal to $p_i$.
输出格式
The minimum number of cows that must be lying.
输入输出样例
输入 #1
2 G 3 L 5
输出 #1
0
It is possible that no cow is lying.
C++ 编辑器
输入
输出
可保存默认模板;新题优先使用已保存模板。
当前快捷键仅展示,暂不支持修改。
- 撤销
Ctrl / ⌘ + Z - 重做
Ctrl / ⌘ + Y - 查找
Ctrl / ⌘ + F - 全选
Ctrl / ⌘ + A - 复制
Ctrl / ⌘ + C - 剪切
Ctrl / ⌘ + X - 粘贴
Ctrl / ⌘ + V - 自动排版
工具栏排版按钮 - 草稿保存
编辑时自动保存到本机
历史
提交记录
状态说明时间源码
AI
作答助手
你好,我是作答助手。可以问思路、复杂度、样例含义或代码报错原因;不会直接给出完整 AC 代码。
确定要清空代码吗?
提交通过
评测结果:Accepted