A8223 | Sum of Digits
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内存限制256MB
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题目描述
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number $n$ . How many times can Gerald put a spell on it until the number becomes one-digit?
输入格式
The first line contains the only integer $n$ ( $0<=n<=10^{100000}$ ). It is guaranteed that $n$ doesn't contain any leading zeroes.
输出格式
Print the number of times a number can be replaced by the sum of its digits until it only contains one digit.
输入输出样例
输入 #1
0
输出 #1
0
输入 #2
10
输出 #2
1
输入 #3
991
输出 #3
3
In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number $10$ . After one casting of a spell it becomes $1$ , and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number $991$ . As one casts a spell the following transformations take place: $991→19→10→1$ . After three transformations the number becomes one-digit.
The second test contains number $10$ . After one casting of a spell it becomes $1$ , and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number $991$ . As one casts a spell the following transformations take place: $991→19→10→1$ . After three transformations the number becomes one-digit.
C++ 编辑器
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评测结果:Accepted