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A66680. 下面程序的 Merge_Sort 函数时间复杂度为( )。void Merge(int a[], int left, int mid, int right) {

单选题

题目描述

下面程序的 Merge_Sort 函数时间复杂度为( )。

void Merge(int a[], int left, int mid, int right) {
    int temp[right - left + 1];
    int i = left;
    int j = mid + 1;
    int k = 0;
    while (i <= mid && j <= right) {
        if (a[i] < a[j])
            temp[k++] = a[i++];
        else
            temp[k++] = a[j++];
    }
    while (i <= mid)
        temp[k++] = a[i++];
    while (j <= right)
        temp[k++] = a[j++];
    for (int m = left, n = 0; m <= right; m++, n++)
        a[m] = temp[n];
}
void Merge_Sort(int a[], int left, int right) {
    if (left == right)
        return;
    int mid = (left + right) / 2;
    Merge_Sort(a, left, mid);
    Merge_Sort(a, mid + 1, right);
    Merge(a, left, mid, right);
}

选项(单选)