A33253. $下面的代码片段用于在双向链表中删除一个节点。请在横线处填入（），使其能正确实现相应功能。void deleteNode(DoublyListNode& head, int value) { DoublyListNode current = head; while (current != nullptr && current->val != value) { current = curren\dots$

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双向链表指针操作节点删除

题目描述

下面的代码片段用于在双向链表中删除一个节点。请在横线处填入（     ），使其能正确实现相应功能。void deleteNode(DoublyListNode*& head, int value) { DoublyListNode* current = head; while (current != nullptr && current->val != value) { current = current->next; } if (current != nullptr) { if (current->prev != nullptr) { ____________________________________ // 在此处填入代码 } else { head = current->next; } if (current->next != nullptr) { current->next->prev = current->prev; } delete current; }}

if (current->next != nullptr) current->next->prev = current->prev;

current->prev->next = current->next;

delete current->next;

current->prev = current->next;

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