A30349. 下面程序的输出为（ ）。#include <iostream>#define N 10using namespace std;int path[N][N];int main() { for (int i = 1; i < N; i++) path[i][0] = i; for (int j = 1; j < N; j++) path[0][j] = j; for (int i = 1; i < …

下面程序的输出为（    ）。

#include <iostream>

#define N 10

using namespace std;

int path[N][N];

int main() {

for (int i = 1; i < N; i++)

     path[i][0] = i;

for (int j = 1; j < N; j++)

     path[0][j] = j;

for (int i = 1; i < N; i++)

     for (int j = 1; j < N; j++)

            path[i][j] = path[i - 1][j] + path[i][j - 1];

cout << path[8][4] << endl;

return 0;

}