A30048. 下面程序是对2024进行唯一分解，最后的结果应该是（ ）。def weiyi(n): factors = {} for i in range(2, n+1): while n % i == 0: if i in factors: factors[i] += 1 else: factors[i] = 1 n //= i return factors

下面程序是对2024进行唯一分解，最后的结果应该是（    ）。

def weiyi(n):

      factors = {}

      for i in range(2, n+1):

            while n % i == 0:

                  if i in factors:

                        factors[i] += 1

                  else:

                        factors[i] = 1

                  n //= i

      return factors