A21948. $执⾏下⾯C++代码可以找出千位与个位的和恰好等于中间两位的四位数，横线处应该填⼊（）int count = 0; int a, bc, d, tmp; for (int i = 1000; i <= 9999; i++) { a = (tmp = i) / 1000; _____________________ bc = tmp / 10; d = tmp - bc * 10; if (a +…$

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知识点

循环结构整数位运算取余与整除

题目描述

执⾏下⾯C++代码可以找出千位与个位的和恰好等于中间两位的四位数，横线处应该填⼊（  ）int count = 0; int a, bc, d, tmp; for (int i = 1000; i <= 9999; i++) { a = (tmp = i) / 1000; _____________________ bc = tmp / 10; d = tmp - bc * 10; if (a + d == bc) { count++; } } cout << count;

tmp= i / 10;

tmp = i % 100;

tmp -= a * 1000;

tmp= i- i%1000;

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