A21100. 设二叉树共有n个结点,函数 preorderTraversal 的时间复杂度为O(n),空间复杂度为O(n)。( )class TreeNode: def __init__(self, x): self.val = x self.left = None self.right = None def preorder(root, res): if root is None: return res.a…
判断题
困难
知识点
题目描述
设二叉树共有n个结点,函数 preorderTraversal 的时间复杂度为O(n),空间复杂度为O(n)。( )
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None
def preorder(root, res):
if root is None:
return
res.append(root.val)
preorder(root.left, res)
preorder(root.right, res)
def preorderTraversal(root):
res = []
preorder(root, res)
return res
if __name__ == "__main__":
root = TreeNode(1)
root.right = TreeNode(2)
root.right.left = TreeNode(3)
result = preorderTraversal(root)
print("前序遍历结果: ", result)
选项(单选)
答案解析
详细答案解析为会员权益,按每日次数查看。
开通 / 升级会员
上一题
下一题