A18331. $如下数字图形在通过执行后续的 C++ 代码时，输入 10 来输出。横线处应填入的代码是（）。1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 1 0 1 0 0 0 0 0 0 1 1 0 0 1 0 0 0 0 0 1 1 0 0 0 1 0 0 0 0 1 1 0 0 0 0 1 0 0 0 1 1 0 0 0 0 0 1 0 0 1 1 0 0 0 0 0 \dots$

单选题较易

知识点

循环结构条件判断二维图形输出

题目描述

如下数字图形在通过执行后续的 C++ 代码时，输入 10 来输出。横线处应填入的代码是（    ）。1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 1 0 1 0 0 0 0 0 0 1 1 0 0 1 0 0 0 0 0 1 1 0 0 0 1 0 0 0 0 1 1 0 0 0 0 1 0 0 0 1 1 0 0 0 0 0 1 0 0 1 1 0 0 0 0 0 0 1 0 1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1int N; cin >> N; for (int i = 1; i < N + 1; i++) { for (int j = 1; j < N + 1; j++) if (________) cout << "1 "; else cout << "0 "; cout << endl; }

i == j and i == 1 and j == 1 and i == N and j == N

i == j or i == 1 or j == 1 or i == N or j == N

i == j or i == 0 or j == 0 or i == (N + 1) or j == (N + 1)

i == j and i == 1 and j == 1 and i == (N + 1) and j == (N + 1)

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