A16438. Accumulator Apex
编程题
普及/提高-
知识点
题目描述
Allyn is playing a new strategy game called "Accumulator Apex". In this game, Allyn is given the initial value of an integer $x$ , referred to as the accumulator, and $k$ lists of integers. Allyn can make multiple turns. On each turn, Allyn can withdraw the leftmost element from any non-empty list and add it to the accumulator $x$ if the resulting $x$ is non-negative. Allyn can end the game at any moment. The goal of the game is to get the largest possible value of the accumulator $x$ . Please help Allyn find the largest possible value of the accumulator $x$ they can get in this game.
输入格式
The first line of the input contains two integers $x$ and $k$ ( $0 \leq x \leq 10^9, 1 \leq k \leq 10^5$ ) — the initial value of the accumulator $x$ and the number of lists. The next $k$ lines contain the description of lists: an integer $l_i$ ( $l_i \ge 1$ ) followed on the same line by $l_i$ elements of the list in the order from left to right. Each element of lists does not exceed $10^9$ by the absolute value, and the total size of all lists does not exceed $10^5$ .
输出格式
The sole line of the output should contain the largest value of the accumulator $x$ Allyn can get.
输入输出样例
输入 #1
1 3 2 -1 2 2 -2 3 2 -3 4
输出 #1
4
输入 #2
1 2 3 -1 -1 4 4 1 -3 -4 8
输出 #2
4
说明/提示
In the first input, we start with $x = 1$ . Then, we can take the first integer from the first list and get $x = 0$ — adding the next integer $2$ from the first list we get $x = 2$ . After that, we can add the integers from the second list and obtain $x = 3$ . Finally, we can add the integers from the third list and obtain $x = 4$ .
In the second input, we can add the first integer from the second list and get $x = 2$ . Then, by adding the elements from the first list, we get $x = 4$ . We cannot add more integers to increase $x$ .
In the second input, we can add the first integer from the second list and get $x = 2$ . Then, by adding the elements from the first list, we get $x = 4$ . We cannot add more integers to increase $x$ .