A16249 | Candy Party (Hard Version)
时间限制1s
内存限制256MB
通过 / 提交0/0
题目描述
This is the hard version of the problem. The only difference is that in this version everyone must give candies to no more than one person and receive candies from no more than one person. Note that a submission cannot pass both versions of the problem at the same time. You can make hacks only if both versions of the problem are solved.
After Zhongkao examination, Daniel and his friends are going to have a party. Everyone will come with some candies.
There will be $n$ people at the party. Initially, the $i$ -th person has $a_i$ candies. During the party, they will swap their candies. To do this, they will line up in an arbitrary order and everyone will do the following no more than once:
- Choose an integer $p$ ( $1 \le p \le n$ ) and a non-negative integer $x$ , then give his $2^{x}$ candies to the $p$ -th person. Note that one cannot give more candies than currently he has (he might receive candies from someone else before) and he cannot give candies to himself.
Daniel likes fairness, so he will be happy if and only if everyone receives candies from no more than one person. Meanwhile, his friend Tom likes average, so he will be happy if and only if all the people have the same number of candies after all swaps.
Determine whether there exists a way to swap candies, so that both Daniel and Tom will be happy after the swaps.
After Zhongkao examination, Daniel and his friends are going to have a party. Everyone will come with some candies.
There will be $n$ people at the party. Initially, the $i$ -th person has $a_i$ candies. During the party, they will swap their candies. To do this, they will line up in an arbitrary order and everyone will do the following no more than once:
- Choose an integer $p$ ( $1 \le p \le n$ ) and a non-negative integer $x$ , then give his $2^{x}$ candies to the $p$ -th person. Note that one cannot give more candies than currently he has (he might receive candies from someone else before) and he cannot give candies to himself.
Daniel likes fairness, so he will be happy if and only if everyone receives candies from no more than one person. Meanwhile, his friend Tom likes average, so he will be happy if and only if all the people have the same number of candies after all swaps.
Determine whether there exists a way to swap candies, so that both Daniel and Tom will be happy after the swaps.
输入格式
The first line of input contains a single integer $t$ ( $1\le t\le 1000$ ) — the number of test cases. The description of test cases follows.
The first line of each test case contains a single integer $n$ ( $2\le n\le 2\cdot 10^5$ ) — the number of people at the party.
The second line of each test case contains $n$ integers $a_1,a_2,\ldots,a_n$ ( $1\le a_i\le 10^9$ ) — the number of candies each person has.
It is guaranteed that the sum of $n$ over all test cases does not exceed $2\cdot 10^5$ .
The first line of each test case contains a single integer $n$ ( $2\le n\le 2\cdot 10^5$ ) — the number of people at the party.
The second line of each test case contains $n$ integers $a_1,a_2,\ldots,a_n$ ( $1\le a_i\le 10^9$ ) — the number of candies each person has.
It is guaranteed that the sum of $n$ over all test cases does not exceed $2\cdot 10^5$ .
输出格式
For each test case, print "Yes" (without quotes) if exists a way to swap candies to make both Daniel and Tom happy, and print "No" (without quotes) otherwise.
You can output the answer in any case (upper or lower). For example, the strings "yEs", "yes", "Yes", and "YES" will be recognized as positive responses.
You can output the answer in any case (upper or lower). For example, the strings "yEs", "yes", "Yes", and "YES" will be recognized as positive responses.
输入输出样例
输入 #1
6 3 2 4 3 5 1 2 3 4 5 6 1 4 7 1 5 4 2 20092043 20092043 12 9 9 8 2 4 4 3 5 1 1 1 1 6 2 12 7 16 11 12
输出 #1
Yes Yes No Yes No Yes
In the first test case, the second person gives $1$ candy to the first person, then all people have $3$ candies.
In the second test case, the fourth person gives $1$ candy to the second person, the fifth person gives $2$ candies to the first person, the third person does nothing. And after the swaps everyone has $3$ candies.
In the third test case, it's impossible for all people to have the same number of candies.
In the fourth test case, the two people do not need to do anything.
In the second test case, the fourth person gives $1$ candy to the second person, the fifth person gives $2$ candies to the first person, the third person does nothing. And after the swaps everyone has $3$ candies.
In the third test case, it's impossible for all people to have the same number of candies.
In the fourth test case, the two people do not need to do anything.
C++ 编辑器
输入
输出
可保存默认模板;新题优先使用已保存模板。
当前快捷键仅展示,暂不支持修改。
- 撤销
Ctrl / ⌘ + Z - 重做
Ctrl / ⌘ + Y - 查找
Ctrl / ⌘ + F - 全选
Ctrl / ⌘ + A - 复制
Ctrl / ⌘ + C - 剪切
Ctrl / ⌘ + X - 粘贴
Ctrl / ⌘ + V - 自动排版
工具栏排版按钮 - 草稿保存
编辑时自动保存到本机
历史
提交记录
状态说明时间源码
AI
作答助手
你好,我是作答助手。可以问思路、复杂度、样例含义或代码报错原因;不会直接给出完整 AC 代码。
确定要清空代码吗?
提交通过
评测结果:Accepted