A16204. How Much Does Daytona Cost?
编程题
普及/提高-
知识点
题目描述
We define an integer to be the most common on a subsegment, if its number of occurrences on that subsegment is larger than the number of occurrences of any other integer in that subsegment. A subsegment of an array is a consecutive segment of elements in the array $a$ .
Given an array $a$ of size $n$ , and an integer $k$ , determine if there exists a non-empty subsegment of $a$ where $k$ is the most common element.
Given an array $a$ of size $n$ , and an integer $k$ , determine if there exists a non-empty subsegment of $a$ where $k$ is the most common element.
输入格式
Each test consists of multiple test cases. The first line contains a single integer $t$ ( $1 \le t \le 1000$ ) — the number of test cases. The description of test cases follows.
The first line of each test case contains two integers $n$ and $k$ ( $1 \le n \le 100$ , $1 \le k \le 100$ ) — the number of elements in array and the element which must be the most common.
The second line of each test case contains $n$ integers $a_1$ , $a_2$ , $a_3$ , $\dots$ , $a_n$ ( $1 \le a_i \le 100$ ) — elements of the array.
The first line of each test case contains two integers $n$ and $k$ ( $1 \le n \le 100$ , $1 \le k \le 100$ ) — the number of elements in array and the element which must be the most common.
The second line of each test case contains $n$ integers $a_1$ , $a_2$ , $a_3$ , $\dots$ , $a_n$ ( $1 \le a_i \le 100$ ) — elements of the array.
输出格式
For each test case output "YES" if there exists a subsegment in which $k$ is the most common element, and "NO" otherwise.
You can output the answer in any case (for example, the strings "yEs", "yes", "Yes", and "YES" will be recognized as a positive answer).
You can output the answer in any case (for example, the strings "yEs", "yes", "Yes", and "YES" will be recognized as a positive answer).
输入输出样例
输入 #1
7 5 4 1 4 3 4 1 4 1 2 3 4 4 5 6 43 5 60 4 2 2 5 1 5 4 1 5 3 3 1 1 3 3 5 3 3 4 1 5 5
输出 #1
YES NO NO YES YES YES YES
说明/提示
In the first test case we need to check if there is a subsegment where the most common element is $4$ .
On the subsegment $[2,5]$ the elements are $4, \ 3, \ 4, \ 1$ .
- $4$ appears $2$ times;
- $1$ appears $1$ time;
- $3$ appears $1$ time.
This means that $4$ is the most common element on the subsegment $[2, 5]$ , so there exists a subsegment where $4$ is the most common element.
On the subsegment $[2,5]$ the elements are $4, \ 3, \ 4, \ 1$ .
- $4$ appears $2$ times;
- $1$ appears $1$ time;
- $3$ appears $1$ time.
This means that $4$ is the most common element on the subsegment $[2, 5]$ , so there exists a subsegment where $4$ is the most common element.