A16146 | Panda Meetups
时间限制1s
内存限制256MB
通过 / 提交0/0
题目描述
The red pandas are in town to meet their relatives, the blue pandas! The town is modeled by a number line.
The pandas have already planned their meetup, but the schedule keeps changing. You are given $q$ updates of the form x t c.
- If $c < 0$ , it means $|c|$ more red pandas enter the number line at position $x$ and time $t$ . Then, each unit of time, they can each independently move one unit in either direction across the number line, or not move at all.
- If $c > 0$ , it means that $c$ more blue pandas check position $x$ for red pandas at time $t$ . If a blue panda does not meet a red panda at that specific location and time, they dejectedly leave the number line right away. If there is a red panda at a position at the same time a blue panda checks it, they form a friendship and leave the number line. Each red panda can form a friendship with at most one blue panda and vice versa.
The updates will be given in order of non-decreasing $x$ values. After each update, please print the maximum number of friendships if the red pandas move in an optimal order based on all the updates given in the input above (and including) this update.
The order in which a red panda moves can change between updates.
The pandas have already planned their meetup, but the schedule keeps changing. You are given $q$ updates of the form x t c.
- If $c < 0$ , it means $|c|$ more red pandas enter the number line at position $x$ and time $t$ . Then, each unit of time, they can each independently move one unit in either direction across the number line, or not move at all.
- If $c > 0$ , it means that $c$ more blue pandas check position $x$ for red pandas at time $t$ . If a blue panda does not meet a red panda at that specific location and time, they dejectedly leave the number line right away. If there is a red panda at a position at the same time a blue panda checks it, they form a friendship and leave the number line. Each red panda can form a friendship with at most one blue panda and vice versa.
The updates will be given in order of non-decreasing $x$ values. After each update, please print the maximum number of friendships if the red pandas move in an optimal order based on all the updates given in the input above (and including) this update.
The order in which a red panda moves can change between updates.
输入格式
The first line contains $q$ ( $1 \leq q \leq 2 \cdot 10^5$ ) – the number of updates.
The $i$ -th line of the next $q$ lines consists of $3$ integers $x_i$ , $t_i$ and $c_i$ ( $0 \leq x_i \leq 10^9$ , $0 \leq t_i \leq 10^9$ , $0 < |c_i| \leq 1000$ ) – the description of the $i$ -th update.
It is guaranteed that the $x_i$ will be given in non-decreasing order.
The $i$ -th line of the next $q$ lines consists of $3$ integers $x_i$ , $t_i$ and $c_i$ ( $0 \leq x_i \leq 10^9$ , $0 \leq t_i \leq 10^9$ , $0 < |c_i| \leq 1000$ ) – the description of the $i$ -th update.
It is guaranteed that the $x_i$ will be given in non-decreasing order.
输出格式
After each update, print the maximum number of friendships that can be formed.
输入输出样例
输入 #1
5 0 6 3 4 2 -5 7 4 -6 10 5 100 10 8 7
输出 #1
0 3 3 3 10
输入 #2
5 0 6 3 4 2 -5 7 4 -6 10 5 100 11 8 7
输出 #2
0 3 3 3 9
输入 #3
7 0 8 6 2 7 -2 3 1 -6 5 3 -8 7 3 -3 8 0 -2 8 2 1
输出 #3
0 0 6 6 6 6 7
输入 #4
4 0 0 -3 0 0 2 0 0 4 0 0 -10
输出 #4
0 2 3 6
In the first example, the number of friendships after each update can be optimized as follows:
1. $3$ blue pandas now check for red pandas at position $0$ at time $6$ . There are no red pandas anywhere, so there are no friendships.
2. $5$ red pandas now appear at position $4$ and time $2$ . $4$ of the red pandas can travel to position $0$ at time $6$ , where $3$ of them can make friendships with the $3$ existing blue pandas.
3. $6$ red pandas now appear at position $7$ and time $4$ . No new blue pandas are added, so the maximum number of friendships is still $3$ .
4. $100$ blue pandas now appear at position $10$ and time $5$ . No red pandas can reach them at a time of $5$ , so no new friendships are created.
5. $7$ blue pandas now appear at position $10$ and time $8$ . $6$ of the red pandas at position $7$ and time $4$ , along with $1$ red panda at position $4$ and time $2$ , can reach $7$ of the blue pandas at position $10$ at time $8$ , adding $7$ new friendships. This brings the total to $10$ friendships.
1. $3$ blue pandas now check for red pandas at position $0$ at time $6$ . There are no red pandas anywhere, so there are no friendships.
2. $5$ red pandas now appear at position $4$ and time $2$ . $4$ of the red pandas can travel to position $0$ at time $6$ , where $3$ of them can make friendships with the $3$ existing blue pandas.
3. $6$ red pandas now appear at position $7$ and time $4$ . No new blue pandas are added, so the maximum number of friendships is still $3$ .
4. $100$ blue pandas now appear at position $10$ and time $5$ . No red pandas can reach them at a time of $5$ , so no new friendships are created.
5. $7$ blue pandas now appear at position $10$ and time $8$ . $6$ of the red pandas at position $7$ and time $4$ , along with $1$ red panda at position $4$ and time $2$ , can reach $7$ of the blue pandas at position $10$ at time $8$ , adding $7$ new friendships. This brings the total to $10$ friendships.
C++ 编辑器
输入
输出
可保存默认模板;新题优先使用已保存模板。
当前快捷键仅展示,暂不支持修改。
- 撤销
Ctrl / ⌘ + Z - 重做
Ctrl / ⌘ + Y - 查找
Ctrl / ⌘ + F - 全选
Ctrl / ⌘ + A - 复制
Ctrl / ⌘ + C - 剪切
Ctrl / ⌘ + X - 粘贴
Ctrl / ⌘ + V - 自动排版
工具栏排版按钮 - 草稿保存
编辑时自动保存到本机
历史
提交记录
状态说明时间源码
AI
作答助手
你好,我是作答助手。可以问思路、复杂度、样例含义或代码报错原因;不会直接给出完整 AC 代码。
确定要清空代码吗?
提交通过
评测结果:Accepted