A16072 | Ambitious Kid
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内存限制256MB
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题目描述
Chaneka, Pak Chanek's child, is an ambitious kid, so Pak Chanek gives her the following problem to test her ambition.
Given an array of integers $[A_1, A_2, A_3, \ldots, A_N]$ . In one operation, Chaneka can choose one element, then increase or decrease the element's value by $1$ . Chaneka can do that operation multiple times, even for different elements.
What is the minimum number of operations that must be done to make it such that $A_1 \times A_2 \times A_3 \times \ldots \times A_N = 0$ ?
Given an array of integers $[A_1, A_2, A_3, \ldots, A_N]$ . In one operation, Chaneka can choose one element, then increase or decrease the element's value by $1$ . Chaneka can do that operation multiple times, even for different elements.
What is the minimum number of operations that must be done to make it such that $A_1 \times A_2 \times A_3 \times \ldots \times A_N = 0$ ?
输入格式
The first line contains a single integer $N$ ( $1 \leq N \leq 10^5$ ).
The second line contains $N$ integers $A_1, A_2, A_3, \ldots, A_N$ ( $-10^5 \leq A_i \leq 10^5$ ).
The second line contains $N$ integers $A_1, A_2, A_3, \ldots, A_N$ ( $-10^5 \leq A_i \leq 10^5$ ).
输出格式
An integer representing the minimum number of operations that must be done to make it such that $A_1 \times A_2 \times A_3 \times \ldots \times A_N = 0$ .
输入输出样例
输入 #1
3 2 -6 5
输出 #1
2
输入 #2
1 -3
输出 #2
3
输入 #3
5 0 -1 0 1 0
输出 #3
0
In the first example, initially, $A_1\times A_2\times A_3=2\times(-6)\times5=-60$ . Chaneka can do the following sequence of operations:
1. Decrease the value of $A_1$ by $1$ . Then, $A_1\times A_2\times A_3=1\times(-6)\times5=-30$
2. Decrease the value of $A_1$ by $1$ . Then, $A_1\times A_2\times A_3=0\times(-6)\times5=0$
In the third example, Chaneka does not have to do any operations, because from the start, it already holds that $A_1\times A_2\times A_3\times A_4\times A_5=0\times(-1)\times0\times1\times0=0$
1. Decrease the value of $A_1$ by $1$ . Then, $A_1\times A_2\times A_3=1\times(-6)\times5=-30$
2. Decrease the value of $A_1$ by $1$ . Then, $A_1\times A_2\times A_3=0\times(-6)\times5=0$
In the third example, Chaneka does not have to do any operations, because from the start, it already holds that $A_1\times A_2\times A_3\times A_4\times A_5=0\times(-1)\times0\times1\times0=0$
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评测结果：Accepted