A15969 | Array Painting
时间限制1s
内存限制256MB
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题目描述
You are given an array of $n$ integers, where each integer is either $0$ , $1$ , or $2$ . Initially, each element of the array is blue.
Your goal is to paint each element of the array red. In order to do so, you can perform operations of two types:
- pay one coin to choose a blue element and paint it red;
- choose a red element which is not equal to $0$ and a blue element adjacent to it, decrease the chosen red element by $1$ , and paint the chosen blue element red.
What is the minimum number of coins you have to spend to achieve your goal?
Your goal is to paint each element of the array red. In order to do so, you can perform operations of two types:
- pay one coin to choose a blue element and paint it red;
- choose a red element which is not equal to $0$ and a blue element adjacent to it, decrease the chosen red element by $1$ , and paint the chosen blue element red.
What is the minimum number of coins you have to spend to achieve your goal?
输入格式
The first line contains one integer $n$ ( $1 \le n \le 2 \cdot 10^5$ ).
The second line contains $n$ integers $a_1, a_2, \dots, a_n$ ( $0 \le a_i \le 2$ ).
The second line contains $n$ integers $a_1, a_2, \dots, a_n$ ( $0 \le a_i \le 2$ ).
输出格式
Print one integer — the minimum number of coins you have to spend in order to paint all elements red.
输入输出样例
输入 #1
3 0 2 0
输出 #1
1
输入 #2
4 0 0 1 1
输出 #2
2
输入 #3
7 0 1 0 0 1 0 2
输出 #3
4
In the first example, you can paint all elements red with having to spend only one coin as follows:
1. paint the $2$ -nd element red by spending one coin;
2. decrease the $2$ -nd element by $1$ and paint the $1$ -st element red;
3. decrease the $2$ -nd element by $1$ and paint the $3$ -rd element red.
In the second example, you can paint all elements red spending only two coins as follows:
1. paint the $4$ -th element red by spending one coin;
2. decrease the $4$ -th element by $1$ and paint the $3$ -rd element red;
3. paint the $1$ -st element red by spending one coin;
4. decrease the $3$ -rd element by $1$ and paint the $2$ -nd element red.
1. paint the $2$ -nd element red by spending one coin;
2. decrease the $2$ -nd element by $1$ and paint the $1$ -st element red;
3. decrease the $2$ -nd element by $1$ and paint the $3$ -rd element red.
In the second example, you can paint all elements red spending only two coins as follows:
1. paint the $4$ -th element red by spending one coin;
2. decrease the $4$ -th element by $1$ and paint the $3$ -rd element red;
3. paint the $1$ -st element red by spending one coin;
4. decrease the $3$ -rd element by $1$ and paint the $2$ -nd element red.
C++ 编辑器
输入
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评测结果:Accepted