测评会员优惠活动进行中 · 开通 VIP,有效期内测评不限次 VIP 优惠中 · 测评不限次 立即查看

A15965. Ian and Array Sorting

编程题 普及/提高-

题目描述

To thank Ian, Mary gifted an array $a$ of length $n$ to Ian. To make himself look smart, he wants to make the array in non-decreasing order by doing the following finitely many times: he chooses two adjacent elements $a_i$ and $a_{i+1}$ ( $1\le i\le n-1$ ), and increases both of them by $1$ or decreases both of them by $1$ . Note that, the elements of the array can become negative.

As a smart person, you notice that, there are some arrays such that Ian cannot make it become non-decreasing order! Therefore, you decide to write a program to determine if it is possible to make the array in non-decreasing order.

输入格式

The first line contains a single integer $t$ ( $1 \leq t \leq 10^4$ ) — the number of test cases. The description of test cases follows.

The first line of each test case consists of a single integer $n$ ( $2\le n\le 3\cdot10^5$ ) — the number of elements in the array.

The second line of each test case contains $n$ integers $a_1,a_2,\ldots,a_n$ ( $1\le a_i\le 10^9$ ) — the elements of the array $a$ .

It is guaranteed that the sum of $n$ over all test cases does not exceed $3\cdot10^5$ .

输出格式

For each test case, output "YES" if there exists a sequence of operations which make the array non-decreasing, else output "NO".

You may print each letter in any case (for example, "YES", "Yes", "yes", "yEs" will all be recognized as positive answer).

输入输出样例

输入 #1
5
3
1 3 2
2
2 1
4
1 3 5 7
4
2 1 4 3
5
5 4 3 2 1
输出 #1
YES
NO
YES
NO
YES

说明/提示

For the first test case, we can increase $a_2$ and $a_3$ both by $1$ . The array is now $[1, 4, 3]$ .

Then we can decrease $a_1$ and $a_2$ both by $1$ . The array is now $[0, 3, 3]$ , which is sorted in non-decreasing order. So the answer is "YES".

For the second test case, no matter how Ian perform the operations, $a_1$ will always be larger than $a_2$ . So the answer is "NO" and Ian cannot pretend to be smart.

For the third test case, the array is already in non-decreasing order, so Ian does not need to do anything.
上一题 去做题 下一题