A15728. One and Two
编程题
普及/提高-
知识点
题目描述
You are given a sequence $a_1, a_2, \ldots, a_n$ . Each element of $a$ is $1$ or $2$ .
Find out if an integer $k$ exists so that the following conditions are met.
- $1 \leq k \leq n-1$ , and
- $a_1 \cdot a_2 \cdot \ldots \cdot a_k = a_{k+1} \cdot a_{k+2} \cdot \ldots \cdot a_n$ .
If there exist multiple $k$ that satisfy the given condition, print the smallest.
Find out if an integer $k$ exists so that the following conditions are met.
- $1 \leq k \leq n-1$ , and
- $a_1 \cdot a_2 \cdot \ldots \cdot a_k = a_{k+1} \cdot a_{k+2} \cdot \ldots \cdot a_n$ .
If there exist multiple $k$ that satisfy the given condition, print the smallest.
输入格式
Each test contains multiple test cases. The first line contains the number of test cases $t$ ( $1 \le t \le 100$ ). Description of the test cases follows.
The first line of each test case contains one integer $n$ ( $2 \leq n \leq 1000$ ).
The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ( $1 \leq a_i \leq 2$ ).
The first line of each test case contains one integer $n$ ( $2 \leq n \leq 1000$ ).
The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ( $1 \leq a_i \leq 2$ ).
输出格式
For each test case, if there is no such $k$ , print $-1$ .
Otherwise, print the smallest possible $k$ .
Otherwise, print the smallest possible $k$ .
输入输出样例
输入 #1
3 6 2 2 1 2 1 2 3 1 2 1 4 1 1 1 1
输出 #1
2 -1 1
说明/提示
For the first test case, $k=2$ satisfies the condition since $a_1 \cdot a_2 = a_3 \cdot a_4 \cdot a_5 \cdot a_6 = 4$ . $k=3$ also satisfies the given condition, but the smallest should be printed.
For the second test case, there is no $k$ that satisfies $a_1 \cdot a_2 \cdot \ldots \cdot a_k = a_{k+1} \cdot a_{k+2} \cdot \ldots \cdot a_n$
For the third test case, $k=1$ , $2$ , and $3$ satisfy the given condition, so the answer is $1$ .
For the second test case, there is no $k$ that satisfies $a_1 \cdot a_2 \cdot \ldots \cdot a_k = a_{k+1} \cdot a_{k+2} \cdot \ldots \cdot a_n$
For the third test case, $k=1$ , $2$ , and $3$ satisfy the given condition, so the answer is $1$ .