A15706 | Distinct Split
时间限制1s
内存限制256MB
通过 / 提交0/0
题目描述
Let's denote the $f(x)$ function for a string $x$ as the number of distinct characters that the string contains. For example $f(\texttt{abc}) = 3$ , $f(\texttt{bbbbb}) = 1$ , and $f(\texttt{babacaba}) = 3$ .
Given a string $s$ , split it into two non-empty strings $a$ and $b$ such that $f(a) + f(b)$ is the maximum possible. In other words, find the maximum possible value of $f(a) + f(b)$ such that $a + b = s$ (the concatenation of string $a$ and string $b$ is equal to string $s$ ).
Given a string $s$ , split it into two non-empty strings $a$ and $b$ such that $f(a) + f(b)$ is the maximum possible. In other words, find the maximum possible value of $f(a) + f(b)$ such that $a + b = s$ (the concatenation of string $a$ and string $b$ is equal to string $s$ ).
输入格式
The input consists of multiple test cases. The first line contains an integer $t$ ( $1 \leq t \leq 10^4$ ) — the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer $n$ ( $2 \leq n \leq 2\cdot10^5$ ) — the length of the string $s$ .
The second line contains the string $s$ , consisting of lowercase English letters.
It is guaranteed that the sum of $n$ over all test cases does not exceed $2\cdot10^5$ .
The first line of each test case contains an integer $n$ ( $2 \leq n \leq 2\cdot10^5$ ) — the length of the string $s$ .
The second line contains the string $s$ , consisting of lowercase English letters.
It is guaranteed that the sum of $n$ over all test cases does not exceed $2\cdot10^5$ .
输出格式
For each test case, output a single integer — the maximum possible value of $f(a) + f(b)$ such that $a + b = s$ .
输入输出样例
输入 #1
5 2 aa 7 abcabcd 5 aaaaa 10 paiumoment 4 aazz
输出 #1
2 7 2 10 3
For the first test case, there is only one valid way to split $\texttt{aa}$ into two non-empty strings $\texttt{a}$ and $\texttt{a}$ , and $f(\texttt{a}) + f(\texttt{a}) = 1 + 1 = 2$ .
For the second test case, by splitting $\texttt{abcabcd}$ into $\texttt{abc}$ and $\texttt{abcd}$ we can get the answer of $f(\texttt{abc}) + f(\texttt{abcd}) = 3 + 4 = 7$ which is maximum possible.
For the third test case, it doesn't matter how we split the string, the answer will always be $2$ .
For the second test case, by splitting $\texttt{abcabcd}$ into $\texttt{abc}$ and $\texttt{abcd}$ we can get the answer of $f(\texttt{abc}) + f(\texttt{abcd}) = 3 + 4 = 7$ which is maximum possible.
For the third test case, it doesn't matter how we split the string, the answer will always be $2$ .
C++ 编辑器
输入
输出
可保存默认模板;新题优先使用已保存模板。
当前快捷键仅展示,暂不支持修改。
- 撤销
Ctrl / ⌘ + Z - 重做
Ctrl / ⌘ + Y - 查找
Ctrl / ⌘ + F - 全选
Ctrl / ⌘ + A - 复制
Ctrl / ⌘ + C - 剪切
Ctrl / ⌘ + X - 粘贴
Ctrl / ⌘ + V - 自动排版
工具栏排版按钮 - 草稿保存
编辑时自动保存到本机
历史
提交记录
状态说明时间源码
AI
作答助手
你好,我是作答助手。可以问思路、复杂度、样例含义或代码报错原因;不会直接给出完整 AC 代码。
确定要清空代码吗?
提交通过
评测结果:Accepted