A15527 | XOR = Average
时间限制1s
内存限制256MB
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题目描述
You are given an integer $n$ . Find a sequence of $n$ integers $a_1, a_2, \dots, a_n$ such that $1 \leq a_i \leq 10^9$ for all $i$ and $$$$a_1 \oplus a_2 \oplus \dots \oplus a_n = \frac{a_1 + a_2 + \dots + a_n}{n}, $$ where $\\oplus$$$ represents the [bitwise XOR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It can be proven that there exists a sequence of integers that satisfies all the conditions above.
It can be proven that there exists a sequence of integers that satisfies all the conditions above.
输入格式
The first line of input contains $t$ ( $1 \leq t \leq 10^4$ ) — the number of test cases.
The first and only line of each test case contains one integer $n$ ( $1 \leq n \leq 10^5$ ) — the length of the sequence you have to find.
The sum of $n$ over all test cases does not exceed $10^5$ .
The first and only line of each test case contains one integer $n$ ( $1 \leq n \leq 10^5$ ) — the length of the sequence you have to find.
The sum of $n$ over all test cases does not exceed $10^5$ .
输出格式
For each test case, output $n$ space-separated integers $a_1, a_2, \dots, a_n$ satisfying the conditions in the statement.
If there are several possible answers, you can output any of them.
If there are several possible answers, you can output any of them.
输入输出样例
输入 #1
3 1 4 3
输出 #1
69 13 2 8 1 7 7 7
In the first test case, $69 = \frac{69}{1} = 69$ .
In the second test case, $13 \oplus 2 \oplus 8 \oplus 1 = \frac{13 + 2 + 8 + 1}{4} = 6$ .
In the second test case, $13 \oplus 2 \oplus 8 \oplus 1 = \frac{13 + 2 + 8 + 1}{4} = 6$ .
C++ 编辑器
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评测结果:Accepted