A15492. Incinerate

To destroy humanity, The Monster Association sent $n$ monsters to Earth's surface. The $i$ -th monster has health $h_i$ and power $p_i$ .

With his last resort attack, True Spiral Incineration Cannon, Genos can deal $k$ damage to all monsters alive. In other words, Genos can reduce the health of all monsters by $k$ (if $k > 0$ ) with a single attack.

However, after every attack Genos makes, the monsters advance. With their combined efforts, they reduce Genos' attack damage by the power of the $^\dagger$ weakest monster $^\ddagger$ alive. In other words, the minimum $p_i$ among all currently living monsters is subtracted from the value of $k$ after each attack.

$^\dagger$ The Weakest monster is the one with the least power.

$^\ddagger$ A monster is alive if its health is strictly greater than $0$ .

Will Genos be successful in killing all the monsters?

The first line of the input contains a single integer $t$ ( $1 \le t \le 100$ ) — the number of test cases. The description of test cases follows.

The first line of each test case contains two integers, $n$ and $k$ ( $1 \le n, k \le 10^5$ ) — the number of monsters and Genos' initial attack damage. Then two lines follow, each containing $n$ integers describing the arrays $h$ and $p$ ( $1 \le h_i, p_i \le 10^9$ ).

It's guaranteed that the sum of $n$ over all test cases does not exceed $2 \cdot 10^5$ .

For each test case, print the answer — "YES" (without quotes) if Genos could kill all monsters and "NO" otherwise.

In the first example, after Genos' first attack, $h$ and $k$ will update to:

- $h: [11,0,6,2,3,0]$
- $k: 7-1 = 6$

After second attack: - $h: [5,0,0,0,0,0]$
- $k: 6-2 = 4$

After third attack: - $h: [1,0,0,0,0,0]$
- $k: 4-2 = 2$

After fourth attack: - $h: [0,0,0,0,0,0]$

As Genos could kill all monsters, the answer is YES.