A15213 | Good Key, Bad Key
时间限制1s
内存限制256MB
通过 / 提交0/0
题目描述
There are $n$ chests. The $i$ -th chest contains $a_i$ coins. You need to open all $n$ chests in order from chest $1$ to chest $n$ .
There are two types of keys you can use to open a chest:
- a good key, which costs $k$ coins to use;
- a bad key, which does not cost any coins, but will halve all the coins in each unopened chest, including the chest it is about to open. The halving operation will round down to the nearest integer for each chest halved. In other words using a bad key to open chest $i$ will do $a_i = \lfloor{\frac{a_i}{2}\rfloor}$ , $a_{i+1} = \lfloor\frac{a_{i+1}}{2}\rfloor, \dots, a_n = \lfloor \frac{a_n}{2}\rfloor$ ;
- any key (both good and bad) breaks after a usage, that is, it is a one-time use.
You need to use in total $n$ keys, one for each chest. Initially, you have no coins and no keys. If you want to use a good key, then you need to buy it.
During the process, you are allowed to go into debt; for example, if you have $1$ coin, you are allowed to buy a good key worth $k=3$ coins, and your balance will become $-2$ coins.
Find the maximum number of coins you can have after opening all $n$ chests in order from chest $1$ to chest $n$ .
There are two types of keys you can use to open a chest:
- a good key, which costs $k$ coins to use;
- a bad key, which does not cost any coins, but will halve all the coins in each unopened chest, including the chest it is about to open. The halving operation will round down to the nearest integer for each chest halved. In other words using a bad key to open chest $i$ will do $a_i = \lfloor{\frac{a_i}{2}\rfloor}$ , $a_{i+1} = \lfloor\frac{a_{i+1}}{2}\rfloor, \dots, a_n = \lfloor \frac{a_n}{2}\rfloor$ ;
- any key (both good and bad) breaks after a usage, that is, it is a one-time use.
You need to use in total $n$ keys, one for each chest. Initially, you have no coins and no keys. If you want to use a good key, then you need to buy it.
During the process, you are allowed to go into debt; for example, if you have $1$ coin, you are allowed to buy a good key worth $k=3$ coins, and your balance will become $-2$ coins.
Find the maximum number of coins you can have after opening all $n$ chests in order from chest $1$ to chest $n$ .
输入格式
The first line contains a single integer $t$ ( $1 \leq t \leq 10^4$ ) — the number of test cases.
The first line of each test case contains two integers $n$ and $k$ ( $1 \leq n \leq 10^5$ ; $0 \leq k \leq 10^9$ ) — the number of chests and the cost of a good key respectively.
The second line of each test case contains $n$ integers $a_i$ ( $0 \leq a_i \leq 10^9$ ) — the amount of coins in each chest.
The sum of $n$ over all test cases does not exceed $10^5$ .
The first line of each test case contains two integers $n$ and $k$ ( $1 \leq n \leq 10^5$ ; $0 \leq k \leq 10^9$ ) — the number of chests and the cost of a good key respectively.
The second line of each test case contains $n$ integers $a_i$ ( $0 \leq a_i \leq 10^9$ ) — the amount of coins in each chest.
The sum of $n$ over all test cases does not exceed $10^5$ .
输出格式
For each test case output a single integer — the maximum number of coins you can obtain after opening the chests in order from chest $1$ to chest $n$ .
Please note, that the answer for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language (like long long for C++).
Please note, that the answer for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language (like long long for C++).
输入输出样例
输入 #1
5 4 5 10 10 3 1 1 2 1 3 12 10 10 29 12 51 5 74 89 45 18 69 67 67 11 96 23 59 2 57 85 60
输出 #1
11 0 13 60 58
In the first test case, one possible strategy is as follows:
- Buy a good key for $5$ coins, and open chest $1$ , receiving $10$ coins. Your current balance is $0 + 10 - 5 = 5$ coins.
- Buy a good key for $5$ coins, and open chest $2$ , receiving $10$ coins. Your current balance is $5 + 10 - 5 = 10$ coins.
- Use a bad key and open chest $3$ . As a result of using a bad key, the number of coins in chest $3$ becomes $\left\lfloor \frac{3}{2} \right\rfloor = 1$ , and the number of coins in chest $4$ becomes $\left\lfloor \frac{1}{2} \right\rfloor = 0$ . Your current balance is $10 + 1 = 11$ .
- Use a bad key and open chest $4$ . As a result of using a bad key, the number of coins in chest $4$ becomes $\left\lfloor \frac{0}{2} \right\rfloor = 0$ . Your current balance is $11 + 0 = 11$ .
At the end of the process, you have $11$ coins, which can be proven to be maximal.
- Buy a good key for $5$ coins, and open chest $1$ , receiving $10$ coins. Your current balance is $0 + 10 - 5 = 5$ coins.
- Buy a good key for $5$ coins, and open chest $2$ , receiving $10$ coins. Your current balance is $5 + 10 - 5 = 10$ coins.
- Use a bad key and open chest $3$ . As a result of using a bad key, the number of coins in chest $3$ becomes $\left\lfloor \frac{3}{2} \right\rfloor = 1$ , and the number of coins in chest $4$ becomes $\left\lfloor \frac{1}{2} \right\rfloor = 0$ . Your current balance is $10 + 1 = 11$ .
- Use a bad key and open chest $4$ . As a result of using a bad key, the number of coins in chest $4$ becomes $\left\lfloor \frac{0}{2} \right\rfloor = 0$ . Your current balance is $11 + 0 = 11$ .
At the end of the process, you have $11$ coins, which can be proven to be maximal.
C++ 编辑器
输入
输出
可保存默认模板;新题优先使用已保存模板。
当前快捷键仅展示,暂不支持修改。
- 撤销
Ctrl / ⌘ + Z - 重做
Ctrl / ⌘ + Y - 查找
Ctrl / ⌘ + F - 全选
Ctrl / ⌘ + A - 复制
Ctrl / ⌘ + C - 剪切
Ctrl / ⌘ + X - 粘贴
Ctrl / ⌘ + V - 自动排版
工具栏排版按钮 - 草稿保存
编辑时自动保存到本机
历史
提交记录
状态说明时间源码
AI
作答助手
你好,我是作答助手。可以问思路、复杂度、样例含义或代码报错原因;不会直接给出完整 AC 代码。
确定要清空代码吗?
提交通过
评测结果:Accepted