A15008 | String Building
时间限制1s
内存限制256MB
通过 / 提交0/0
题目描述
You are given a string $s$ . You have to determine whether it is possible to build the string $s$ out of strings aa, aaa, bb and/or bbb by concatenating them. You can use the strings aa, aaa, bb and/or bbb any number of times and in any order.
For example:
- aaaabbb can be built as aa $+$ aa $+$ bbb;
- bbaaaaabbb can be built as bb $+$ aaa $+$ aa $+$ bbb;
- aaaaaa can be built as aa $+$ aa $+$ aa;
- abab cannot be built from aa, aaa, bb and/or bbb.
For example:
- aaaabbb can be built as aa $+$ aa $+$ bbb;
- bbaaaaabbb can be built as bb $+$ aaa $+$ aa $+$ bbb;
- aaaaaa can be built as aa $+$ aa $+$ aa;
- abab cannot be built from aa, aaa, bb and/or bbb.
输入格式
The first line contains one integer $t$ ( $1 \le t \le 1000$ ) — the number of test cases.
Each test case consists of one line containing the string $s$ ( $1 \le |s| \le 50$ ), consisting of characters a and/or b.
Each test case consists of one line containing the string $s$ ( $1 \le |s| \le 50$ ), consisting of characters a and/or b.
输出格式
For each test case, print YES if it is possible to build the string $s$ . Otherwise, print NO.
You may print each letter in any case (for example, YES, yes, Yes will all be recognized as positive answer, NO, no and nO will all be recognized as negative answer).
You may print each letter in any case (for example, YES, yes, Yes will all be recognized as positive answer, NO, no and nO will all be recognized as negative answer).
输入输出样例
输入 #1
8 aaaabbb bbaaaaabbb aaaaaa abab a b aaaab bbaaa
输出 #1
YES YES YES NO NO NO NO YES
The first four test cases of the example are described in the statement.
C++ 编辑器
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你好,我是作答助手。可以问思路、复杂度、样例含义或代码报错原因;不会直接给出完整 AC 代码。
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评测结果:Accepted