A14897 | Good Pairs
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内存限制256MB
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题目描述
You are given an array $a_1, a_2, \ldots, a_n$ of positive integers. A good pair is a pair of indices $(i, j)$ with $1 \leq i, j \leq n$ such that, for all $1 \leq k \leq n$ , the following equality holds:
$$$$ |a_i - a_k| + |a_k - a_j| = |a_i - a_j|, $$ where $|x|$ denotes the absolute value of $x$ .</p><p>Find a good pair. Note that $i$ can be equal to $j$$$.
$$$$ |a_i - a_k| + |a_k - a_j| = |a_i - a_j|, $$ where $|x|$ denotes the absolute value of $x$ .</p><p>Find a good pair. Note that $i$ can be equal to $j$$$.
输入格式
The input consists of multiple test cases. The first line contains a single integer $t$ ( $1 \leq t \leq 1000$ ) — the number of test cases. Description of the test cases follows.
The first line of each test case contains an integer $n$ ( $1 \leq n \leq 10^5$ ) — the length of the array.
The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ( $1 \leq a_i \leq 10^9$ ) where $a_i$ is the $i$ -th element of the array.
The sum of $n$ for all test cases is at most $2 \cdot 10^5$ .
The first line of each test case contains an integer $n$ ( $1 \leq n \leq 10^5$ ) — the length of the array.
The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ( $1 \leq a_i \leq 10^9$ ) where $a_i$ is the $i$ -th element of the array.
The sum of $n$ for all test cases is at most $2 \cdot 10^5$ .
输出格式
For each test case, print a single line with two space-separated indices $i$ and $j$ which form a good pair of the array. The case $i=j$ is allowed. It can be shown that such a pair always exists. If there are multiple good pairs, print any of them.
输入输出样例
输入 #1
3 3 5 2 7 5 1 4 2 2 3 1 2
输出 #1
2 3 1 2 1 1
In the first case, for $i = 2$ and $j = 3$ the equality holds true for all $k$ :
- $k = 1$ : $|a_2 - a_1| + |a_1 - a_3| = |2 - 5| + |5 - 7| = 5 = |2 - 7| = |a_2-a_3|$ ,
- $k = 2$ : $|a_2 - a_2| + |a_2 - a_3| = |2 - 2| + |2 - 7| = 5 = |2 - 7| = |a_2-a_3|$ ,
- $k = 3$ : $|a_2 - a_3| + |a_3 - a_3| = |2 - 7| + |7 - 7| = 5 = |2 - 7| = |a_2-a_3|$ .
- $k = 1$ : $|a_2 - a_1| + |a_1 - a_3| = |2 - 5| + |5 - 7| = 5 = |2 - 7| = |a_2-a_3|$ ,
- $k = 2$ : $|a_2 - a_2| + |a_2 - a_3| = |2 - 2| + |2 - 7| = 5 = |2 - 7| = |a_2-a_3|$ ,
- $k = 3$ : $|a_2 - a_3| + |a_3 - a_3| = |2 - 7| + |7 - 7| = 5 = |2 - 7| = |a_2-a_3|$ .
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评测结果:Accepted