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A14831 | Make AP

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题目描述

Polycarp has $3$ positive integers $a$ , $b$ and $c$ . He can perform the following operation exactly once.

- Choose a positive integer $m$ and multiply exactly one of the integers $a$ , $b$ or $c$ by $m$ .

Can Polycarp make it so that after performing the operation, the sequence of three numbers $a$ , $b$ , $c$ (in this order) forms an [arithmetic progression](https://en.wikipedia.org/wiki/Arithmetic_progression)? Note that you cannot change the order of $a$ , $b$ and $c$ .

Formally, a sequence $x_1, x_2, \dots, x_n$ is called an arithmetic progression (AP) if there exists a number $d$ (called "common difference") such that $x_{i+1}=x_i+d$ for all $i$ from $1$ to $n-1$ . In this problem, $n=3$ .

For example, the following sequences are AP: $[5, 10, 15]$ , $[3, 2, 1]$ , $[1, 1, 1]$ , and $[13, 10, 7]$ . The following sequences are not AP: $[1, 2, 4]$ , $[0, 1, 0]$ and $[1, 3, 2]$ .

You need to answer $t$ independent test cases.

输入格式

The first line contains the number $t$ ( $1 \le t \le 10^4$ ) — the number of test cases.

Each of the following $t$ lines contains $3$ integers $a$ , $b$ , $c$ ( $1 \le a, b, c \le 10^8$ ).

输出格式

For each test case print "YES" (without quotes) if Polycarp can choose a positive integer $m$ and multiply exactly one of the integers $a$ , $b$ or $c$ by $m$ to make $[a, b, c]$ be an arithmetic progression. Print "NO" (without quotes) otherwise.

You can print YES and NO in any (upper or lower) case (for example, the strings yEs, yes, Yes and YES will be recognized as a positive answer).

输入输出样例

输入 #1
11
10 5 30
30 5 10
1 2 3
1 6 3
2 6 3
1 1 1
1 1 2
1 1 3
1 100000000 1
2 1 1
1 2 2
输出 #1
YES
YES
YES
YES
NO
YES
NO
YES
YES
NO
YES
C++ 编辑器
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