A14695. And It's Non-Zero
编程题
普及/提高-
知识点
题目描述
You are given an array consisting of all integers from $[l, r]$ inclusive. For example, if $l = 2$ and $r = 5$ , the array would be $[2, 3, 4, 5]$ . What's the minimum number of elements you can delete to make the [bitwise AND](https://en.wikipedia.org/wiki/Bitwise_operation#AND) of the array non-zero?
A bitwise AND is a binary operation that takes two equal-length binary representations and performs the AND operation on each pair of the corresponding bits.
A bitwise AND is a binary operation that takes two equal-length binary representations and performs the AND operation on each pair of the corresponding bits.
输入格式
The first line contains one integer $t$ ( $1 \leq t \leq 10^4$ ) — the number of test cases. Then $t$ cases follow.
The first line of each test case contains two integers $l$ and $r$ ( $1 \leq l \leq r \leq 2 \cdot 10^5$ ) — the description of the array.
The first line of each test case contains two integers $l$ and $r$ ( $1 \leq l \leq r \leq 2 \cdot 10^5$ ) — the description of the array.
输出格式
For each test case, output a single integer — the answer to the problem.
输入输出样例
输入 #1
5 1 2 2 8 4 5 1 5 100000 200000
输出 #1
1 3 0 2 31072
说明/提示
In the first test case, the array is $[1, 2]$ . Currently, the bitwise AND is $0$ , as $1\ \& \ 2 = 0$ . However, after deleting $1$ (or $2$ ), the array becomes $[2]$ (or $[1]$ ), and the bitwise AND becomes $2$ (or $1$ ). This can be proven to be the optimal, so the answer is $1$ .
In the second test case, the array is $[2, 3, 4, 5, 6, 7, 8]$ . Currently, the bitwise AND is $0$ . However, after deleting $4$ , $5$ , and $8$ , the array becomes $[2, 3, 6, 7]$ , and the bitwise AND becomes $2$ . This can be proven to be the optimal, so the answer is $3$ . Note that there may be other ways to delete $3$ elements.
In the second test case, the array is $[2, 3, 4, 5, 6, 7, 8]$ . Currently, the bitwise AND is $0$ . However, after deleting $4$ , $5$ , and $8$ , the array becomes $[2, 3, 6, 7]$ , and the bitwise AND becomes $2$ . This can be proven to be the optimal, so the answer is $3$ . Note that there may be other ways to delete $3$ elements.