A14396. Cherry
编程题
普及/提高-
知识点
题目描述
You are given $n$ integers $a_1, a_2, \ldots, a_n$ . Find the maximum value of $max(a_l, a_{l + 1}, \ldots, a_r) \cdot min(a_l, a_{l + 1}, \ldots, a_r)$ over all pairs $(l, r)$ of integers for which $1 \le l < r \le n$ .
输入格式
The first line contains a single integer $t$ ( $1 \le t \le 10\,000$ ) — the number of test cases.
The first line of each test case contains a single integer $n$ ( $2 \le n \le 10^5$ ).
The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ( $1 \le a_i \le 10^6$ ).
It is guaranteed that the sum of $n$ over all test cases doesn't exceed $3 \cdot 10^5$ .
The first line of each test case contains a single integer $n$ ( $2 \le n \le 10^5$ ).
The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ( $1 \le a_i \le 10^6$ ).
It is guaranteed that the sum of $n$ over all test cases doesn't exceed $3 \cdot 10^5$ .
输出格式
For each test case, print a single integer — the maximum possible value of the product from the statement.
输入输出样例
输入 #1
4 3 2 4 3 4 3 2 3 1 2 69 69 6 719313 273225 402638 473783 804745 323328
输出 #1
12 6 4761 381274500335
说明/提示
Let $f(l, r) = max(a_l, a_{l + 1}, \ldots, a_r) \cdot min(a_l, a_{l + 1}, \ldots, a_r)$ .
In the first test case,
- $f(1, 2) = max(a_1, a_2) \cdot min(a_1, a_2) = max(2, 4) \cdot min(2, 4) = 4 \cdot 2 = 8$ .
- $f(1, 3) = max(a_1, a_2, a_3) \cdot min(a_1, a_2, a_3) = max(2, 4, 3) \cdot min(2, 4, 3) = 4 \cdot 2 = 8$ .
- $f(2, 3) = max(a_2, a_3) \cdot min(a_2, a_3) = max(4, 3) \cdot min(4, 3) = 4 \cdot 3 = 12$ .
So the maximum is $f(2, 3) = 12$ .
In the second test case, the maximum is $f(1, 2) = f(1, 3) = f(2, 3) = 6$ .
In the first test case,
- $f(1, 2) = max(a_1, a_2) \cdot min(a_1, a_2) = max(2, 4) \cdot min(2, 4) = 4 \cdot 2 = 8$ .
- $f(1, 3) = max(a_1, a_2, a_3) \cdot min(a_1, a_2, a_3) = max(2, 4, 3) \cdot min(2, 4, 3) = 4 \cdot 2 = 8$ .
- $f(2, 3) = max(a_2, a_3) \cdot min(a_2, a_3) = max(4, 3) \cdot min(4, 3) = 4 \cdot 3 = 12$ .
So the maximum is $f(2, 3) = 12$ .
In the second test case, the maximum is $f(1, 2) = f(1, 3) = f(2, 3) = 6$ .