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A14344. Median Queries

编程题 普及/提高-

题目描述

This is an interactive problem.

There is a secret permutation $p$ ( $1$ -indexed) of numbers from $1$ to $n$ . More formally, for $1 \leq i \leq n$ , $1 \leq p[i] \leq n$ and for $1 \leq i < j \leq n$ , $p[i] \neq p[j]$ . It is known that $p[1]<p[2]$ .

In $1$ query, you give $3$ distinct integers $a,b,c$ ( $1 \leq a,b,c \leq n$ ), and receive the median of $\{|p[a]-p[b]|,|p[b]-p[c]|,|p[a]-p[c]|\}$ .

In this case, the median is the $2$ -nd element ( $1$ -indexed) of the sequence when sorted in non-decreasing order. The median of $\{4,6,2\}$ is $4$ and the median of $\{0,123,33\}$ is $33$ .

Can you find the secret permutation in not more than $2n+420$ queries?

Note: the grader is not adaptive: the permutation is fixed before any queries are made.

输入格式

The first line of input contains a single integer $t$ $(1 \leq t \leq 1000)$ — the number of testcases.

The first line of each testcase consists of a single integer $n$ $(20 \leq n \leq 100000)$ — the length of the secret permutation.

It is guaranteed that the sum of $n$ over all test cases does not exceed $100000$ .

输出格式

For each testcase, you begin the interaction by reading $n$ .

To perform a query, output "? a b c" where $a,b,c$ is the $3$ indices you want to use for the query.

Numbers have to satisfy $1 \leq a,b,c \leq n$ and $a \neq b$ , $b \neq c$ , $a \neq c$ .

For each query, you will receive a single integer $x$ : the median of $\{|p[a]-p[b]|,|p[b]-p[c]|,|p[a]-p[c]|\}$ .

In case your query is invalid or you asked more than $2n+420$ queries, the interactor will print "−1" and will finish interaction. You will receive Wrong answer verdict. Make sure to exit immediately to avoid getting other verdicts.

When you have determined the secret permutation, output "! p\[1\] p\[2\] ... p\[n\]". If the secret permutation is correct, the interactor will print "1". Otherwise, the interactor will print "-1" and will finish interaction. You will receive Wrong answer verdict. Make sure to exit immediately to avoid getting other verdicts.

After printing a query do not forget to output the end of line and flush the output. Otherwise, you will get Idleness limit exceeded verdict.

To do this, use:

- fflush(stdout) or cout.flush() in C++;
- System.out.flush() in Java;
- flush(output) in Pascal;
- stdout.flush() in Python;
- see documentation for other languages.

Hacks:

To hack, use the following format of test:

The first line should contain a single integer $t$ ( $1 \leq t \leq 1000$ ) — the number of testcases.

The first line of each testcase should contain a single integer $n$ ( $20 \leq n \leq 100000$ ) — the length of the secret permutation.

The following line of should contain $n$ integers $p[1],p[2],p[3],\ldots,p[n]$ . $p[1]<p[2]$ and $p$ must be a permutation of integers from $1$ to $n$ .

You must ensure that the sum of $n$ over all testcases does not exceed $100000$ .

输入输出样例

输入 #1
1
20

6

9

1
输出 #1
? 1 5 2

? 20 19 2

! 9 10 19 7 16 18 11 14 15 6 20 8 17 4 5 3 12 2 13 1

说明/提示

The secret permutation is $\{9,10,19,7,16,18,11,14,15,6,20,8,17,4,5,3,12,2,13,1\}$ .

For the first query, the values of $(a,b,c)$ is $(1,5,2)$ . Since $p[1]=9$ , $p[5]=16$ and $p[2]=10$ . The return value is the median of $\{|9-16|,|16-10|,|9-10|\}$ which is $6$ .

For the second query, the values of $(a,b,c)$ is $(20,19,2)$ . Since $p[20]=1$ , $p[19]=13$ and $p[2]=10$ . The return value is the median of $\{|1-13|,|13-10|,|1-10|\}$ which is $9$ .

By some miracle, we have figured out that the secret permutation is $\{9,10,19,7,16,18,11,14,15,6,20,8,17,4,5,3,12,2,13,1\}$ . We output it and receive $1$ from the interactor, meaning that we have guessed the secret permutation correctly.
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