A14265 | Chaotic Merge
时间限制1s
内存限制256MB
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题目描述
You are given two strings $x$ and $y$ , both consist only of lowercase Latin letters. Let $|s|$ be the length of string $s$ .
Let's call a sequence $a$ a merging sequence if it consists of exactly $|x|$ zeros and exactly $|y|$ ones in some order.
A merge $z$ is produced from a sequence $a$ by the following rules:
- if $a_i=0$ , then remove a letter from the beginning of $x$ and append it to the end of $z$ ;
- if $a_i=1$ , then remove a letter from the beginning of $y$ and append it to the end of $z$ .
Two merging sequences $a$ and $b$ are different if there is some position $i$ such that $a_i \neq b_i$ .
Let's call a string $z$ chaotic if for all $i$ from $2$ to $|z|$ $z_{i-1} \neq z_i$ .
Let $s[l,r]$ for some $1 \le l \le r \le |s|$ be a substring of consecutive letters of $s$ , starting from position $l$ and ending at position $r$ inclusive.
Let $f(l_1, r_1, l_2, r_2)$ be the number of different merging sequences of $x[l_1,r_1]$ and $y[l_2,r_2]$ that produce chaotic merges. Note that only non-empty substrings of $x$ and $y$ are considered.
Calculate $\sum \limits_{1 \le l_1 \le r_1 \le |x| \\ 1 \le l_2 \le r_2 \le |y|} f(l_1, r_1, l_2, r_2)$ . Output the answer modulo $998\,244\,353$ .
Let's call a sequence $a$ a merging sequence if it consists of exactly $|x|$ zeros and exactly $|y|$ ones in some order.
A merge $z$ is produced from a sequence $a$ by the following rules:
- if $a_i=0$ , then remove a letter from the beginning of $x$ and append it to the end of $z$ ;
- if $a_i=1$ , then remove a letter from the beginning of $y$ and append it to the end of $z$ .
Two merging sequences $a$ and $b$ are different if there is some position $i$ such that $a_i \neq b_i$ .
Let's call a string $z$ chaotic if for all $i$ from $2$ to $|z|$ $z_{i-1} \neq z_i$ .
Let $s[l,r]$ for some $1 \le l \le r \le |s|$ be a substring of consecutive letters of $s$ , starting from position $l$ and ending at position $r$ inclusive.
Let $f(l_1, r_1, l_2, r_2)$ be the number of different merging sequences of $x[l_1,r_1]$ and $y[l_2,r_2]$ that produce chaotic merges. Note that only non-empty substrings of $x$ and $y$ are considered.
Calculate $\sum \limits_{1 \le l_1 \le r_1 \le |x| \\ 1 \le l_2 \le r_2 \le |y|} f(l_1, r_1, l_2, r_2)$ . Output the answer modulo $998\,244\,353$ .
输入格式
The first line contains a string $x$ ( $1 \le |x| \le 1000$ ).
The second line contains a string $y$ ( $1 \le |y| \le 1000$ ).
Both strings consist only of lowercase Latin letters.
The second line contains a string $y$ ( $1 \le |y| \le 1000$ ).
Both strings consist only of lowercase Latin letters.
输出格式
Print a single integer — the sum of $f(l_1, r_1, l_2, r_2)$ over $1 \le l_1 \le r_1 \le |x|$ and $1 \le l_2 \le r_2 \le |y|$ modulo $998\,244\,353$ .
输入输出样例
输入 #1
aaa bb
输出 #1
24
输入 #2
code forces
输出 #2
1574
输入 #3
aaaaa aaa
输出 #3
0
输入 #4
justamassivetesttocheck howwellyouhandlemodulooperations
输出 #4
667387032
In the first example there are:
- $6$ pairs of substrings "a" and "b", each with valid merging sequences "01" and "10";
- $3$ pairs of substrings "a" and "bb", each with a valid merging sequence "101";
- $4$ pairs of substrings "aa" and "b", each with a valid merging sequence "010";
- $2$ pairs of substrings "aa" and "bb", each with valid merging sequences "0101" and "1010";
- $2$ pairs of substrings "aaa" and "b", each with no valid merging sequences;
- $1$ pair of substrings "aaa" and "bb" with a valid merging sequence "01010";
Thus, the answer is $6 \cdot 2 + 3 \cdot 1 + 4 \cdot 1 + 2 \cdot 2 + 2 \cdot 0 + 1 \cdot 1 = 24$ .
- $6$ pairs of substrings "a" and "b", each with valid merging sequences "01" and "10";
- $3$ pairs of substrings "a" and "bb", each with a valid merging sequence "101";
- $4$ pairs of substrings "aa" and "b", each with a valid merging sequence "010";
- $2$ pairs of substrings "aa" and "bb", each with valid merging sequences "0101" and "1010";
- $2$ pairs of substrings "aaa" and "b", each with no valid merging sequences;
- $1$ pair of substrings "aaa" and "bb" with a valid merging sequence "01010";
Thus, the answer is $6 \cdot 2 + 3 \cdot 1 + 4 \cdot 1 + 2 \cdot 2 + 2 \cdot 0 + 1 \cdot 1 = 24$ .
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评测结果:Accepted