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A14089. Let's Go Hiking

编程题 普及/提高-

题目描述

On a weekend, Qingshan suggests that she and her friend Daniel go hiking. Unfortunately, they are busy high school students, so they can only go hiking on scratch paper.

A permutation $p$ is written from left to right on the paper. First Qingshan chooses an integer index $x$ ( $1\le x\le n$ ) and tells it to Daniel. After that, Daniel chooses another integer index $y$ ( $1\le y\le n$ , $y \ne x$ ).

The game progresses turn by turn and as usual, Qingshan moves first. The rules follow:

- If it is Qingshan's turn, Qingshan must change $x$ to such an index $x'$ that $1\le x'\le n$ , $|x'-x|=1$ , $x'\ne y$ , and $p_{x'}<p_x$ at the same time.
- If it is Daniel's turn, Daniel must change $y$ to such an index $y'$ that $1\le y'\le n$ , $|y'-y|=1$ , $y'\ne x$ , and $p_{y'}>p_y$ at the same time.

The person who can't make her or his move loses, and the other wins. You, as Qingshan's fan, are asked to calculate the number of possible $x$ to make Qingshan win in the case both players play optimally.

输入格式

The first line contains a single integer $n$ ( $2\le n\le 10^5$ ) — the length of the permutation.

The second line contains $n$ distinct integers $p_1,p_2,\dots,p_n$ ( $1\le p_i\le n$ ) — the permutation.

输出格式

Print the number of possible values of $x$ that Qingshan can choose to make her win.

输入输出样例

输入 #1
5
1 2 5 4 3
输出 #1
1
输入 #2
7
1 2 4 6 5 3 7
输出 #2
0

说明/提示

In the first test case, Qingshan can only choose $x=3$ to win, so the answer is $1$ .

In the second test case, if Qingshan will choose $x=4$ , Daniel can choose $y=1$ . In the first turn (Qingshan's) Qingshan chooses $x'=3$ and changes $x$ to $3$ . In the second turn (Daniel's) Daniel chooses $y'=2$ and changes $y$ to $2$ . Qingshan can't choose $x'=2$ because $y=2$ at this time. Then Qingshan loses.
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