A14022 | Regular Bracket Sequence
时间限制1s
内存限制256MB
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题目描述
A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) are regular, while )(, (() and (()))( are not. Let's call a regular bracket sequence "RBS".
You are given a sequence $s$ of $n$ characters (, ), and/or ?. There is exactly one character ( and exactly one character ) in this sequence.
You have to replace every character ? with either ) or ( (different characters ? can be replaced with different brackets). You cannot reorder the characters, remove them, insert other characters, and each ? must be replaced.
Determine if it is possible to obtain an RBS after these replacements.
You are given a sequence $s$ of $n$ characters (, ), and/or ?. There is exactly one character ( and exactly one character ) in this sequence.
You have to replace every character ? with either ) or ( (different characters ? can be replaced with different brackets). You cannot reorder the characters, remove them, insert other characters, and each ? must be replaced.
Determine if it is possible to obtain an RBS after these replacements.
输入格式
The first line contains one integer $t$ ( $1 \le t \le 1000$ ) — the number of test cases.
Each test case consists of one line containing $s$ ( $2 \le |s| \le 100$ ) — a sequence of characters (, ), and/or ?. There is exactly one character ( and exactly one character ) in this sequence.
Each test case consists of one line containing $s$ ( $2 \le |s| \le 100$ ) — a sequence of characters (, ), and/or ?. There is exactly one character ( and exactly one character ) in this sequence.
输出格式
For each test case, print YES if it is possible to obtain a regular bracket sequence, or NO otherwise}.
You may print each letter in any case (for example, YES, Yes, yes, yEs will all be recognized as positive answer).
You may print each letter in any case (for example, YES, Yes, yes, yEs will all be recognized as positive answer).
输入输出样例
输入 #1
5 () (?) (??) ??() )?(?
输出 #1
YES NO YES YES NO
In the first test case, the sequence is already an RBS.
In the third test case, you can obtain an RBS as follows: ()() or (()).
In the fourth test case, you can obtain an RBS as follows: ()().
In the third test case, you can obtain an RBS as follows: ()() or (()).
In the fourth test case, you can obtain an RBS as follows: ()().
C++ 编辑器
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输出
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评测结果:Accepted