A13714. Permutation Forgery

A permutation of length $n$ is an array consisting of $n$ distinct integers from $1$ to $n$ in arbitrary order. For example, $[2,3,1,5,4]$ is a permutation, but $[1,2,2]$ is not a permutation ( $2$ appears twice in the array) and $[1,3,4]$ is also not a permutation ( $n=3$ but there is $4$ in the array).

Let $p$ be any permutation of length $n$ . We define the fingerprint $F(p)$ of $p$ as the sorted array of sums of adjacent elements in $p$ . More formally,

$$$$F(p)=\mathrm{sort}([p_1+p_2,p_2+p_3,\ldots,p_{n-1}+p_n]). $$ </p><p>For example, if $n=4$ and $p=\[1,4,2,3\],$ then the fingerprint is given by $F(p)=\\mathrm{sort}(\[1+4,4+2,2+3\])=\\mathrm{sort}(\[5,6,5\])=\[5,5,6\]$ .</p><p>You are given a permutation $p$ of length $n$ . Your task is to find a <span class="tex-font-style-bf">different</span> permutation $p'$ with the same fingerprint. Two permutations $p$ and $p'$ are considered different if there is some index $i$ such that $p\_i \\ne p'\_i$$$.

Each test contains multiple test cases. The first line contains the number of test cases $t$ ( $1 \le t \le 668$ ). Description of the test cases follows.

The first line of each test case contains a single integer $n$ ( $2\le n\le 100$ ) — the length of the permutation.

The second line of each test case contains $n$ integers $p_1,\ldots,p_n$ ( $1\le p_i\le n$ ). It is guaranteed that $p$ is a permutation.

For each test case, output $n$ integers $p'_1,\ldots, p'_n$ — a permutation such that $p'\ne p$ and $F(p')=F(p)$ .

We can prove that for every permutation satisfying the input constraints, a solution exists.

If there are multiple solutions, you may output any.

In the first test case, $F(p)=\mathrm{sort}([1+2])=[3]$ .

And $F(p')=\mathrm{sort}([2+1])=[3]$ .

In the second test case, $F(p)=\mathrm{sort}([2+1,1+6,6+5,5+4,4+3])=\mathrm{sort}([3,7,11,9,7])=[3,7,7,9,11]$ .

And $F(p')=\mathrm{sort}([1+2,2+5,5+6,6+3,3+4])=\mathrm{sort}([3,7,11,9,7])=[3,7,7,9,11]$ .

In the third test case, $F(p)=\mathrm{sort}([2+4,4+3,3+1,1+5])=\mathrm{sort}([6,7,4,6])=[4,6,6,7]$ .

And $F(p')=\mathrm{sort}([3+1,1+5,5+2,2+4])=\mathrm{sort}([4,6,7,6])=[4,6,6,7]$ .