题库练习 Prefix Flip (Easy Version)
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A13624 | Prefix Flip (Easy Version)

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题目描述

This is the easy version of the problem. The difference between the versions is the constraint on $n$ and the required number of operations. You can make hacks only if all versions of the problem are solved.

There are two binary strings $a$ and $b$ of length $n$ (a binary string is a string consisting of symbols $0$ and $1$ ). In an operation, you select a prefix of $a$ , and simultaneously invert the bits in the prefix ( $0$ changes to $1$ and $1$ changes to $0$ ) and reverse the order of the bits in the prefix.

For example, if $a=001011$ and you select the prefix of length $3$ , it becomes $011011$ . Then if you select the entire string, it becomes $001001$ .

Your task is to transform the string $a$ into $b$ in at most $3n$ operations. It can be proved that it is always possible.

输入格式

The first line contains a single integer $t$ ( $1\le t\le 1000$ ) — the number of test cases. Next $3t$ lines contain descriptions of test cases.

The first line of each test case contains a single integer $n$ ( $1\le n\le 1000$ ) — the length of the binary strings.

The next two lines contain two binary strings $a$ and $b$ of length $n$ .

It is guaranteed that the sum of $n$ across all test cases does not exceed $1000$ .

输出格式

For each test case, output an integer $k$ ( $0\le k\le 3n$ ), followed by $k$ integers $p_1,\ldots,p_k$ ( $1\le p_i\le n$ ). Here $k$ is the number of operations you use and $p_i$ is the length of the prefix you flip in the $i$ -th operation.

输入输出样例

输入 #1
5
2
01
10
5
01011
11100
2
01
01
10
0110011011
1000110100
1
0
1
输出 #1
3 1 2 1
6 5 2 5 3 1 2
0
9 4 1 2 10 4 1 2 1 5
1 1
C++ 编辑器
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