A13305. EhAb AnD gCd
编程题
普及/提高-
知识点
题目描述
You are given a positive integer $x$ . Find any such $2$ positive integers $a$ and $b$ such that $GCD(a,b)+LCM(a,b)=x$ .
As a reminder, $GCD(a,b)$ is the greatest integer that divides both $a$ and $b$ . Similarly, $LCM(a,b)$ is the smallest integer such that both $a$ and $b$ divide it.
It's guaranteed that the solution always exists. If there are several such pairs $(a, b)$ , you can output any of them.
As a reminder, $GCD(a,b)$ is the greatest integer that divides both $a$ and $b$ . Similarly, $LCM(a,b)$ is the smallest integer such that both $a$ and $b$ divide it.
It's guaranteed that the solution always exists. If there are several such pairs $(a, b)$ , you can output any of them.
输入格式
The first line contains a single integer $t$ $(1 \le t \le 100)$ — the number of testcases.
Each testcase consists of one line containing a single integer, $x$ $(2 \le x \le 10^9)$ .
Each testcase consists of one line containing a single integer, $x$ $(2 \le x \le 10^9)$ .
输出格式
For each testcase, output a pair of positive integers $a$ and $b$ ( $1 \le a, b \le 10^9)$ such that $GCD(a,b)+LCM(a,b)=x$ . It's guaranteed that the solution always exists. If there are several such pairs $(a, b)$ , you can output any of them.
输入输出样例
输入 #1
2 2 14
输出 #1
1 1 6 4
说明/提示
In the first testcase of the sample, $GCD(1,1)+LCM(1,1)=1+1=2$ .
In the second testcase of the sample, $GCD(6,4)+LCM(6,4)=2+12=14$ .
In the second testcase of the sample, $GCD(6,4)+LCM(6,4)=2+12=14$ .