A12737. Heidi Learns Hashing (Medium)
编程题
普及/提高-
知识点
题目描述
After learning about polynomial hashing, Heidi decided to learn about shift-xor hashing. In particular, she came across this interesting problem.
Given a bitstring $y \in \{0,1\}^n$ find out the number of different $k$ ( $0 \leq k < n$ ) such that there exists $x \in \{0,1\}^n$ for which $y = x \oplus \mbox{shift}^k(x).$
In the above, $\oplus$ is the xor operation and $\mbox{shift}^k$ is the operation of shifting a bitstring cyclically to the right $k$ times. For example, $001 \oplus 111 = 110$ and $\mbox{shift}^3(00010010111000) = 00000010010111$ .
Given a bitstring $y \in \{0,1\}^n$ find out the number of different $k$ ( $0 \leq k < n$ ) such that there exists $x \in \{0,1\}^n$ for which $y = x \oplus \mbox{shift}^k(x).$
In the above, $\oplus$ is the xor operation and $\mbox{shift}^k$ is the operation of shifting a bitstring cyclically to the right $k$ times. For example, $001 \oplus 111 = 110$ and $\mbox{shift}^3(00010010111000) = 00000010010111$ .
输入格式
The first line contains an integer $n$ ( $1 \leq n \leq 2 \cdot 10^5$ ), the length of the bitstring $y$ .
The second line contains the bitstring $y$ .
The second line contains the bitstring $y$ .
输出格式
Output a single integer: the number of suitable values of $k$ .
输入输出样例
输入 #1
4 1010
输出 #1
3
输入 #2
16
输出 #2
NO
说明/提示
In the first example:
- $1100\oplus \mbox{shift}^1(1100) = 1010$
- $1000\oplus \mbox{shift}^2(1000) = 1010$
- $0110\oplus \mbox{shift}^3(0110) = 1010$
There is no $x$ such that $x \oplus x = 1010$ , hence the answer is $3$ .
- $1100\oplus \mbox{shift}^1(1100) = 1010$
- $1000\oplus \mbox{shift}^2(1000) = 1010$
- $0110\oplus \mbox{shift}^3(0110) = 1010$
There is no $x$ such that $x \oplus x = 1010$ , hence the answer is $3$ .