A12683. From S To T
编程题
普及/提高-
知识点
题目描述
You are given three strings $s$ , $t$ and $p$ consisting of lowercase Latin letters. You may perform any number (possibly, zero) operations on these strings.
During each operation you choose any character from $p$ , erase it from $p$ and insert it into string $s$ (you may insert this character anywhere you want: in the beginning of $s$ , in the end or between any two consecutive characters).
For example, if $p$ is aba, and $s$ is de, then the following outcomes are possible (the character we erase from $p$ and insert into $s$ is highlighted):
- aba $\rightarrow$ ba, de $\rightarrow$ ade;
- aba $\rightarrow$ ba, de $\rightarrow$ dae;
- aba $\rightarrow$ ba, de $\rightarrow$ dea;
- aba $\rightarrow$ aa, de $\rightarrow$ bde;
- aba $\rightarrow$ aa, de $\rightarrow$ dbe;
- aba $\rightarrow$ aa, de $\rightarrow$ deb;
- aba $\rightarrow$ ab, de $\rightarrow$ ade;
- aba $\rightarrow$ ab, de $\rightarrow$ dae;
- aba $\rightarrow$ ab, de $\rightarrow$ dea;
Your goal is to perform several (maybe zero) operations so that $s$ becomes equal to $t$ . Please determine whether it is possible.
Note that you have to answer $q$ independent queries.
During each operation you choose any character from $p$ , erase it from $p$ and insert it into string $s$ (you may insert this character anywhere you want: in the beginning of $s$ , in the end or between any two consecutive characters).
For example, if $p$ is aba, and $s$ is de, then the following outcomes are possible (the character we erase from $p$ and insert into $s$ is highlighted):
- aba $\rightarrow$ ba, de $\rightarrow$ ade;
- aba $\rightarrow$ ba, de $\rightarrow$ dae;
- aba $\rightarrow$ ba, de $\rightarrow$ dea;
- aba $\rightarrow$ aa, de $\rightarrow$ bde;
- aba $\rightarrow$ aa, de $\rightarrow$ dbe;
- aba $\rightarrow$ aa, de $\rightarrow$ deb;
- aba $\rightarrow$ ab, de $\rightarrow$ ade;
- aba $\rightarrow$ ab, de $\rightarrow$ dae;
- aba $\rightarrow$ ab, de $\rightarrow$ dea;
Your goal is to perform several (maybe zero) operations so that $s$ becomes equal to $t$ . Please determine whether it is possible.
Note that you have to answer $q$ independent queries.
输入格式
The first line contains one integer $q$ ( $1 \le q \le 100$ ) — the number of queries. Each query is represented by three consecutive lines.
The first line of each query contains the string $s$ ( $1 \le |s| \le 100$ ) consisting of lowercase Latin letters.
The second line of each query contains the string $t$ ( $1 \le |t| \le 100$ ) consisting of lowercase Latin letters.
The third line of each query contains the string $p$ ( $1 \le |p| \le 100$ ) consisting of lowercase Latin letters.
The first line of each query contains the string $s$ ( $1 \le |s| \le 100$ ) consisting of lowercase Latin letters.
The second line of each query contains the string $t$ ( $1 \le |t| \le 100$ ) consisting of lowercase Latin letters.
The third line of each query contains the string $p$ ( $1 \le |p| \le 100$ ) consisting of lowercase Latin letters.
输出格式
For each query print YES if it is possible to make $s$ equal to $t$ , and NO otherwise.
You may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).
You may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).
输入输出样例
输入 #1
4 ab acxb cax a aaaa aaabbcc a aaaa aabbcc ab baaa aaaaa
输出 #1
YES YES NO NO
说明/提示
In the first test case there is the following sequence of operation:
1. $s = $ ab, $t = $ acxb, $p = $ cax;
2. $s = $ acb, $t = $ acxb, $p = $ ax;
3. $s = $ acxb, $t = $ acxb, $p = $ a.
In the second test case there is the following sequence of operation:
1. $s = $ a, $t = $ aaaa, $p = $ aaabbcc;
2. $s = $ aa, $t = $ aaaa, $p = $ aabbcc;
3. $s = $ aaa, $t = $ aaaa, $p = $ abbcc;
4. $s = $ aaaa, $t = $ aaaa, $p = $ bbcc.
1. $s = $ ab, $t = $ acxb, $p = $ cax;
2. $s = $ acb, $t = $ acxb, $p = $ ax;
3. $s = $ acxb, $t = $ acxb, $p = $ a.
In the second test case there is the following sequence of operation:
1. $s = $ a, $t = $ aaaa, $p = $ aaabbcc;
2. $s = $ aa, $t = $ aaaa, $p = $ aabbcc;
3. $s = $ aaa, $t = $ aaaa, $p = $ abbcc;
4. $s = $ aaaa, $t = $ aaaa, $p = $ bbcc.