A12525 | Hate "A"
时间限制1s
内存限制256MB
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题目描述
Bob has a string $s$ consisting of lowercase English letters. He defines $s'$ to be the string after removing all "a" characters from $s$ (keeping all other characters in the same order). He then generates a new string $t$ by concatenating $s$ and $s'$ . In other words, $t=s+s'$ (look at notes for an example).
You are given a string $t$ . Your task is to find some $s$ that Bob could have used to generate $t$ . It can be shown that if an answer exists, it will be unique.
You are given a string $t$ . Your task is to find some $s$ that Bob could have used to generate $t$ . It can be shown that if an answer exists, it will be unique.
输入格式
The first line of input contains a string $t$ ( $1 \leq |t| \leq 10^5$ ) consisting of lowercase English letters.
输出格式
Print a string $s$ that could have generated $t$ . It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
输入输出样例
输入 #1
aaaaa
输出 #1
aaaaa
输入 #2
aacaababc
输出 #2
:(
输入 #3
ababacacbbcc
输出 #3
ababacac
输入 #4
baba
输出 #4
:(
In the first example, we have $s = $ "aaaaa", and $s' = $ "".
In the second example, no such $s$ can work that will generate the given $t$ .
In the third example, we have $s = $ "ababacac", and $s' = $ "bbcc", and $t = s + s' = $ "ababacacbbcc".
In the second example, no such $s$ can work that will generate the given $t$ .
In the third example, we have $s = $ "ababacac", and $s' = $ "bbcc", and $t = s + s' = $ "ababacacbbcc".
C++ 编辑器
输入
输出
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评测结果:Accepted