题库练习 Single Wildcard Pattern Matching
← 上一题 下一题 →

A11871 | Single Wildcard Pattern Matching

时间限制1s
内存限制256MB
通过 / 提交0/0

题目描述

You are given two strings $s$ and $t$ . The string $s$ consists of lowercase Latin letters and at most one wildcard character '\*', the string $t$ consists only of lowercase Latin letters. The length of the string $s$ equals $n$ , the length of the string $t$ equals $m$ .

The wildcard character '\*' in the string $s$ (if any) can be replaced with an arbitrary sequence (possibly empty) of lowercase Latin letters. No other character of $s$ can be replaced with anything. If it is possible to replace a wildcard character '\*' in $s$ to obtain a string $t$ , then the string $t$ matches the pattern $s$ .

For example, if $s=$ "aba\*aba" then the following strings match it "abaaba", "abacaba" and "abazzzaba", but the following strings do not match: "ababa", "abcaaba", "codeforces", "aba1aba", "aba?aba".

If the given string $t$ matches the given string $s$ , print "YES", otherwise print "NO".

输入格式

The first line contains two integers $n$ and $m$ ( $1 \le n, m \le 2 \cdot 10^5$ ) — the length of the string $s$ and the length of the string $t$ , respectively.

The second line contains string $s$ of length $n$ , which consists of lowercase Latin letters and at most one wildcard character '\*'.

The third line contains string $t$ of length $m$ , which consists only of lowercase Latin letters.

输出格式

Print "YES" (without quotes), if you can obtain the string $t$ from the string $s$ . Otherwise print "NO" (without quotes).

输入输出样例

输入 #1
6 10
code*s
codeforces
输出 #1
YES
输入 #2
6 5
vk*cup
vkcup
输出 #2
YES
输入 #3
1 1
v
k
输出 #3
NO
输入 #4
9 6
gfgf*gfgf
gfgfgf
输出 #4
NO
C++ 编辑器
输入
输出