A11770 | Reversing Encryption
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内存限制256MB
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题目描述
A string $s$ of length $n$ can be encrypted by the following algorithm:
- iterate over all divisors of $n$ in decreasing order (i.e. from $n$ to $1$ ),
- for each divisor $d$ , reverse the substring $s[1 \dots d]$ (i.e. the substring which starts at position $1$ and ends at position $d$ ).
For example, the above algorithm applied to the string $s$ ="codeforces" leads to the following changes: "codeforces" $\to$ "secrofedoc" $\to$ "orcesfedoc" $\to$ "rocesfedoc" $\to$ "rocesfedoc" (obviously, the last reverse operation doesn't change the string because $d=1$ ).
You are given the encrypted string $t$ . Your task is to decrypt this string, i.e., to find a string $s$ such that the above algorithm results in string $t$ . It can be proven that this string $s$ always exists and is unique.
- iterate over all divisors of $n$ in decreasing order (i.e. from $n$ to $1$ ),
- for each divisor $d$ , reverse the substring $s[1 \dots d]$ (i.e. the substring which starts at position $1$ and ends at position $d$ ).
For example, the above algorithm applied to the string $s$ ="codeforces" leads to the following changes: "codeforces" $\to$ "secrofedoc" $\to$ "orcesfedoc" $\to$ "rocesfedoc" $\to$ "rocesfedoc" (obviously, the last reverse operation doesn't change the string because $d=1$ ).
You are given the encrypted string $t$ . Your task is to decrypt this string, i.e., to find a string $s$ such that the above algorithm results in string $t$ . It can be proven that this string $s$ always exists and is unique.
输入格式
The first line of input consists of a single integer $n$ ( $1 \le n \le 100$ ) — the length of the string $t$ . The second line of input consists of the string $t$ . The length of $t$ is $n$ , and it consists only of lowercase Latin letters.
输出格式
Print a string $s$ such that the above algorithm results in $t$ .
输入输出样例
输入 #1
10 rocesfedoc
输出 #1
codeforces
输入 #2
16 plmaetwoxesisiht
输出 #2
thisisexampletwo
输入 #3
1 z
输出 #3
z
The first example is described in the problem statement.
C++ 编辑器
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评测结果:Accepted