A11527 | Tricky Alchemy

During the winter holidays, the demand for Christmas balls is exceptionally high. Since it's already $2018$ , the advances in alchemy allow easy and efficient ball creation by utilizing magic crystals.

Grisha needs to obtain some yellow, green and blue balls. It's known that to produce a yellow ball one needs two yellow crystals, green — one yellow and one blue, and for a blue ball, three blue crystals are enough.

Right now there are $A$ yellow and $B$ blue crystals in Grisha's disposal. Find out how many additional crystals he should acquire in order to produce the required number of balls.

The first line features two integers $A$ and $B$ ( $0<=A,B<=10^{9}$ ), denoting the number of yellow and blue crystals respectively at Grisha's disposal.

The next line contains three integers $x$ , $y$ and $z$ ( $0<=x,y,z<=10^{9}$ ) — the respective amounts of yellow, green and blue balls to be obtained.

Print a single integer — the minimum number of crystals that Grisha should acquire in addition.