A11521 | Christmas Spruce
时间限制1s
内存限制256MB
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题目描述
Consider a rooted tree. A rooted tree has one special vertex called the root. All edges are directed from the root. Vertex $u$ is called a child of vertex $v$ and vertex $v$ is called a parent of vertex $u$ if there exists a directed edge from $v$ to $u$ . A vertex is called a leaf if it doesn't have children and has a parent.
Let's call a rooted tree a spruce if its every non-leaf vertex has at least $3$ leaf children. You are given a rooted tree, check whether it's a spruce.
The definition of a rooted tree can be found [here](https://goo.gl/1dqvzz).
Let's call a rooted tree a spruce if its every non-leaf vertex has at least $3$ leaf children. You are given a rooted tree, check whether it's a spruce.
The definition of a rooted tree can be found [here](https://goo.gl/1dqvzz).
输入格式
The first line contains one integer $n$ — the number of vertices in the tree ( $3<=n<=1000$ ). Each of the next $n-1$ lines contains one integer $p_{i}$ ( $1<=i<=n-1$ ) — the index of the parent of the $i+1$ -th vertex ( $1<=p_{i}<=i$ ).
Vertex $1$ is the root. It's guaranteed that the root has at least $2$ children.
Vertex $1$ is the root. It's guaranteed that the root has at least $2$ children.
输出格式
Print "Yes" if the tree is a spruce and "No" otherwise.
输入输出样例
输入 #1
4 1 1 1
输出 #1
Yes
输入 #2
7 1 1 1 2 2 2
输出 #2
No
输入 #3
8 1 1 1 1 3 3 3
输出 #3
Yes
The first example:

The second example:

It is not a spruce, because the non-leaf vertex $1$ has only $2$ leaf children.
The third example:


The second example:

It is not a spruce, because the non-leaf vertex $1$ has only $2$ leaf children.
The third example:

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评测结果:Accepted