A10792. The Holmes Children
编程题
普及/提高-
知识点
题目描述
The Holmes children are fighting over who amongst them is the cleverest.
Mycroft asked Sherlock and Eurus to find value of $f(n)$ , where $f(1)=1$ and for $n>=2$ , $f(n)$ is the number of distinct ordered positive integer pairs $(x,y)$ that satisfy $x+y=n$ and $gcd(x,y)=1$ . The integer $gcd(a,b)$ is the greatest common divisor of $a$ and $b$ .
Sherlock said that solving this was child's play and asked Mycroft to instead get the value of . Summation is done over all positive integers $d$ that divide $n$ .
Eurus was quietly observing all this and finally came up with her problem to astonish both Sherlock and Mycroft.
She defined a $k$ -composite function $F_{k}(n)$ recursively as follows:
She wants them to tell the value of $F_{k}(n)$ modulo $1000000007$ .
Mycroft asked Sherlock and Eurus to find value of $f(n)$ , where $f(1)=1$ and for $n>=2$ , $f(n)$ is the number of distinct ordered positive integer pairs $(x,y)$ that satisfy $x+y=n$ and $gcd(x,y)=1$ . The integer $gcd(a,b)$ is the greatest common divisor of $a$ and $b$ .
Sherlock said that solving this was child's play and asked Mycroft to instead get the value of . Summation is done over all positive integers $d$ that divide $n$ .
Eurus was quietly observing all this and finally came up with her problem to astonish both Sherlock and Mycroft.
She defined a $k$ -composite function $F_{k}(n)$ recursively as follows:
She wants them to tell the value of $F_{k}(n)$ modulo $1000000007$ .
输入格式
A single line of input contains two space separated integers $n$ ( $1<=n<=10^{12}$ ) and $k$ ( $1<=k<=10^{12}$ ) indicating that Eurus asks Sherlock and Mycroft to find the value of $F_{k}(n)$ modulo $1000000007$ .
输出格式
Output a single integer — the value of $F_{k}(n)$ modulo $1000000007$ .
输入输出样例
输入 #1
7 1
输出 #1
6
输入 #2
10 2
输出 #2
4
说明/提示
In the first case, there are $6$ distinct ordered pairs $(1,6)$ , $(2,5)$ , $(3,4)$ , $(4,3)$ , $(5,2)$ and $(6,1)$ satisfying $x+y=7$ and $gcd(x,y)=1$ . Hence, $f(7)=6$ . So, $F_{1}(7)=f(g(7))=f(f(7)+f(1))=f(6+1)=f(7)=6$ .